coefficient of static friction is 1.7329
Explanation:
given data
velocity = 60 mph
acceleration = 17 m/s²
to find out
coefficient of static friction
solution
we will apply here centripetal force equation
that is
m×v²/r = µ × m × g ..................1
here v²/r is centripetal acceleration and m is mass and µ is coefficient static friction so
µ = a / g
µ = 17 / 9.81
µ = 1.7329
so coefficient of static friction is 1.7329
Answer:
73.72
Explanation:
For this subtraction problem, the answer or solution is expressed to the least precise of the numbers we are trying to subtract.
The least precise number is the number with the lowest significant numbers:
105.4 - 31.681
105.4 has 4 significant numbers
31.681 has 5 significant numbers
So;
105.4
- 31.681
------------------
73.719
----------------
The solution is therefore 73.72
Answer:
5*10^25 atoms of carbon
Explanation:
<u>Check from the periodic table:</u>
M(carbon) = 12.01 g/mol
<u>Convert kg into g:</u>
1 kg = 1000 g
<u>Calculate the number of moles of carbon:</u>
n(carbon) = (1000 g) ÷ (12.01 g/mol) = 83.26 mol
<u>Convert moles into number of particles:</u>
#(carbon) = n × NA = 83.26 mol × 6*10^23
= 5*10^25 particles
<em>N</em><em>o</em><em>t</em><em>e</em><em>:</em><em> </em><em>NA represents the Avogadro's Number, which has the value 6.02*10^23 particles/mol</em><em>.</em>
In a moving car the outside looks to be moving. however if viewed from the outside, the car appears to be moving. so motion is relative to the person observing.
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