Answer: The number of gram of ammonia gas () contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.
Explanation:
Given: Volume = 3.0 L
Temperature = 305 K
Pressure = 1.50 atm
Formula used to calculate the number of moles is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
It is known that moles is the mass of substance divided by its molar mass.
Hence, mass of ammonia gas (molar mass = 17.03 g/mol) is as follows.
Thus, we can conclude that the number of gram of ammonia gas () contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.
Yes unless it is a green arrow. Then you have the right away.
Answer:c
Explanation:
Because it will take out the fuel right away
Answer:
(d) 2 pF
Explanation: the charge on capacitor is given by the expression
Q=CV
where Q=charge
C=capacitance
V=voltage across the plate of the capacitor
here we have given Q=500 pF, V=250 volt
using this formula C=
=500××
=2×
=2 pF