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mel-nik [20]
2 years ago
8

Drivers education - Unit 3

Engineering
1 answer:
melamori03 [73]2 years ago
4 0

The following scenarios are pertinent to driving conditions that one may encounter. See the following rules of driving.

<h3>What do you do when the car is forced into the guardrail?</h3>

Best response:

  • I'll keep my hands on the wheel and slow down gradually.
  • The reason I keep my hands on the steering wheel is to avoid losing control.
  • This will allow me to slowly back away from the guard rail.
  • The next phase is to gradually return to the fast lane.
  • Slamming on the brakes at this moment would result in a collision with the car behind.

Scenario 2: When driving on a wet road and the car begins to slide

Best response:

  • It is not advised to accelerate.
  • Pumping the brakes is not recommended.
  • Even lightly depressing and holding down the brake pedal is not recommended.
  • The best thing to do is take one foot off the gas pedal.
  • There should be no severe twists at this time.

Scenario 3: When you are in slow traffic and you hear the siren of an ambulance behind

Best response:

  • The best thing to do at this moment is to go to the right side of the lane and come to a complete stop.
  • This helps to keep the patient in the ambulance alive.
  • It also provide a clear path for the ambulance.
  • Moving to the left is NOT recommended.
  • This will exacerbate the situation. If there is no place to park on the right shoulder of the road, it is preferable to stay in the lane.

Learn more about rules of driving. at;

brainly.com/question/8384066

#SPJ1

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g A 30-m-diameter sedimentation basin has an average water depth of 3.0 m. It is treating 0.3 m3/s wastewater flow. Compute over
stepladder [879]

Answer:

The overflow rate is 4.24×10^-4 m/s.

The detention time is 7069.5 s

Explanation:

Overflow rate is given as volumetric flow rate ÷ area

volumetric flow rate = 0.3 m^3/s

area = πd^2/4 = 3.142×30^2/4 = 706.95 m^2

Overflow rate = 0.3 m^3/s ÷ 706.95 m^2 = 4.24×10^-4 m/s

Detention time = volume ÷ volumetric flow rate

volume = area × depth = 706.95 m^2 × 3 m = 2120.85 m^3

Detention time = 2120.85 m^3 ÷ 0.3 m^3/s = 7069.5 s

6 0
3 years ago
A 0.9% solution of NaCl is considered isotonic to mammalian cells. what molar concentration is this?
natka813 [3]

Answer:

58.44 g/mol The Molarity of this concentration is 0.154 molar

Explanation:

the molar mass of NaCl is 58.44 g/mol,

0.9 % is the same thing as 0.9g of NaCl , so this means that 100 ml's of physiological saline contains 0.9 g of NaCl.  One liter of physiological saline must contain 9 g of NaCl.  We can determine the molarity of a physiological saline solution by dividing 9 g by 58 g... since we have 9 g of NaCl in a liter of physiological saline, but we have 58 grams of NaCl in a mole of NaCl.  When we divide 9 g by 58 g, we find that physiological saline contains 0.154 moles of NaCl per liter.  That means that physiological saline (0.9% NaCl) has a molarity of 0.154 molar.  We can either express this as 0.154 M or 154 millimolar (154 mM).

3 0
4 years ago
On July 23, 1983, Air Canada Flight 143 required 22,300 kg of jet fuel to fly from Montreal to Edmonton. The density of jet fuel
Natasha2012 [34]

Answer:

20, 083 L

Explanation:

The mistake was the result of not using units when converting the 7862 l to Kg. They used the density in pounds hence they multiplied by 1.77 Lb/L and obtained 13597 Lb not Kg as they assumed.

To obtain the amount needed to refuel they subtracted this quantity from the 22,300 Kg required for the trip again obtaining the wrong quantity of 8703 Kg and they converted this to liters by dividing the density to get 4916 L and then placed then 5000 L of fuel

The quantity required was

7862 L * 1.77 Lb/L = 13915.74 Lb (pounds not kilos)

then converting this pounds to Kg by multiplying by  0.454 Kg/L one gets

6173 Kg on board

Amount Required

( 22,300 -6173)  :  16127 Kg

16127 Kg/ 0.803 Kg/L =  20083 L

5 0
3 years ago
Can you reduce energy use without compromising people's basic needs (such as opening a car, cooking food, home lighting, electri
Liono4ka [1.6K]

Answer:

   yes

  • electric and/or hybrid cars
  • microwave ovens
  • LED lighting
  • low-power electronics

Explanation:

Advances in technology and changes in social organization have brought about reductions in energy use on many fronts.

  • hybrid/electric vehicles have reduced transportation energy needs
  • microwave ovens have reduced cooking energy needs
  • LED lighting has reduced lighting energy needs
  • low-power electronics have reduced the energy cost of technology and entertainment
  • heat pumps and insulated windows have reduced energy needs for home heating and cooling
  • zoning laws have reduced the need for travel to work and shopping areas
4 0
3 years ago
A wastewater treatment plant has two primary clarifiers, each 20m in diameter with a 2-m side-water depth. the effluent weirs ar
jasenka [17]

Answer:

overflow rate 20.53 m^3/d/m^2

Detention time 2.34 hr

weir loading  114.06 m^3/d/m

Explanation:

calculation for single clarifier

sewag\  flow Q = \frac{12900}{2} = 6450 m^2/d

surface\  area =\frac{pi}{4}\times diameter ^2 = \frac{pi}{4}\times 20^2

surface area = 314.16 m^2

volume of tankV  = A\times side\ water\ depth

                             =314.16\times 2 = 628.32m^3

Length\ of\  weir = \pi \times diameter of weir

                       = \pi \times 18 = 56.549 m

overflow rate =v_o = \frac{flow}{surface\ area} = \frac{6450}{314.16} = 20.53 m^3/d/m^2

Detention timet_d = \frac{volume}{flow} = \frac{628.32}{6450} \times 24 = 2.34 hr

weir loading= \frac{flow}{weir\ length} = \frac{6450}{56.549} = 114.06 m^3/d/m

6 0
3 years ago
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