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Stels [109]
3 years ago
7

Which statement is true about mass and weight?

Chemistry
2 answers:
PtichkaEL [24]3 years ago
7 0
What’s the question? Is it 123
Mariulka [41]3 years ago
6 0

D. Mass is constant but weight changes based upon the amount of gravity.
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You carry out a titration of a pure weak triprotic acid and only see two major pH jumps. One at 10.0 mL and the second one at 15
mafiozo [28]
23 would be most likely
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The compound 2,2-dimethylpentane has several structural isomers. how many of the isomers are straight-chained?
neonofarm [45]
The answer Is (1)...Straight Isomer when you put them together.





Hope that helps!!!
8 0
3 years ago
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Given that the ka for hocl is 3.5 × 10–8, calculate the k value for the reaction of hocl with oh–.
Harlamova29_29 [7]
Following reaction is involved in above system
HOCl(aq)  ↔  H+(aq) + OCl-<span>(aq)
</span>OCl-(aq) + H2O(l)  ↔ HOCl(aq) + OH-<span>(aq)
</span>
Now, if the system is obeys 1st order kinetics we have
K  = [OCl-][H+<span>]/[HOCl]   ............. (1)
</span>∴ [HOCl-] / [OCl-] = [H+] (1 / 3.0 * 10-8<span>)   ............. (2)
</span>
and now considering that system is obeying 2nd order kinetics, we have
K  = [OH-][HOCl-] / [OCl-] ................. (3<span>)
</span>Subs 2 in 3 we get
K = [OH-][H+] (1 / 3.0 * 10-8<span>)
</span>we know that, [OH-][H+] = 10<span>-14

</span>∴K = 3.3 * 10<span>-7
</span>
Thus, correct answer is e i.e none of these
6 0
3 years ago
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Which of the following shows the abbreviation for an Sl unit of density?
lara [203]

Explanation:

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4 0
3 years ago
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How many moles of chlorine are used up in a reaction that produces 0.35kg of BCl3
maw [93]

4.48 mol Cl2. A reaction that produces 0.35 kg of BCl3 will use 4.48 mol of Cl2.

(a) The <em>balanced chemical equation </em>is

2B + 3Cl2 → 2BCl3

(b) Convert kilograms of BCl3 to moles of BCl3

MM: B = 10.81; Cl = 35.45; BCl3 = 117.16

Moles of BCl3 = 350 g BCl3 x (1 mol BCl3/117.16 g BCl3) = 2.987 mol BCl3

(c) Use the <em>molar ratio</em> of Cl2:BCl3 to calculate the moles of Cl2.

Moles of Cl2 = 2.987 mol BCl3 x (3 mol Cl2/2 mol BCl3) = 4.48 mol Cl2

4 0
3 years ago
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