Answer:
At the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced
Explanation:
At cathode, reduction reaction takes place.
The dissociation of MgI2 in aqueous solution is Mg2+(aq) and 2I−(aq)
Here, the Iodine reduces to 2I−(aq) from state of 0 (MgI2) to state of -1 (2I−(aq))
Hence, at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced
C. quartz and amethyst
Explanation:
Quartz and amethyst can be told apart by their color without performing a streak test on them.
This is because from the given choices, their color is different.
quartz is a colorless
amethyst is purple
- Quartz is silicate mineral purely made of silicon and oxygen.
- Amethyst is a variety of quartz but containing some mineral inclusions that makes its color different.
- Preforming the streak test gives their color to be white.
- This cannot be useful in identifying the minerals they contain.
- Since their natural colors are distinct, it is a more diagnostics tool .
learn more:
Silicate minerals brainly.com/question/4772323
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Answer:
Explanation:
Places near the Equator experience little seasonal variation. They have about the same amount of daylight and darkness throughout the year. These places remain warm year-round. Near the Equator, regions typically have alternating rainy and dry seasons.
Answer:
The answers are: (a )0.0058 M; (b) 0.00681 M; (c) 0.006912 M
Explanation:
Ionic strenght= μ= 1/2 ∑ c z²
Where c is the concentration of each ion (in M) and z is the charge of the ion. So, to calculate the ionic strenght of a solution you have to know the concentration of each ion and their charges. For this, the dissociation equilibrium is required.
a) HCl → H⁺ + Cl⁻
Conc H⁺= 0.00580 M
Conc Cl⁻= 0.00580 M
μ= 1/2 x ((Conc H⁺)(+1)²) + ((Conc Cl⁻)(-1)²
μ= 1/2 x ((0.00580 M) + (0.00580 M))
μ= 0.00580 M
b) CaBr₂ → Ca²⁺ + 2 Br⁻
Conc Ca²⁺= 0.00227 M
Conc Br⁻= 2 x 0.00227 M= 0.00454 M
μ= 1/2 ((Conc Ca²⁺)(+2)² + ((Conc Br⁻)(-1)²)
μ= 1/2 (0.00227 M (4)) + (0.00454 M)
μ= 0.00681 M
c) The solution has two dissociation equilibria:
Mg(NO₃)₂ → Mg²⁺ + 2 NO₃⁻
La(NO₃)₃ → La³⁺ + 3 NO₃⁻
Conc Mg²⁺= 0.000752 M
Conc NO₃⁻= 2 x (0.000752 M) + 3 x (0.000776 M)= 0.003832 M
Conc La³⁺= 0.000776 M
μ= 1/2 ((Conc Mg²⁺)(+2)²)+ ((Conc NO₃⁻)(-1)²) + ((Conc La³⁺)(+3)²)
μ= 1/2 (0.000752 M(4)) + (0.003832 M) + (0.000776 M)(9))
μ= 0.006912 M
