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PolarNik [594]
3 years ago
7

John was considered to be a pillar in the early church?

Chemistry
2 answers:
o-na [289]3 years ago
4 0
Yes he was a pillar in the early church
Vsevolod [243]3 years ago
3 0
True it says in Galatians 2:9 That he was considered to be a pillar in the early church
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Balance the reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1.
Ilia_Sergeevich [38]

Answer:

2H₂O₂ → 2H₂O + O₂

Explanation:

H₂O₂ → H₂O + O₂

The above equation can be balance as illustrated below:

H₂O₂ → H₂O + O₂

There are 2 atoms of O on the left side and a total of 3 atoms on the right side. It can be balance by putting 2 in front of H₂O₂ and 2 in front of H₂O as shown below:

2H₂O₂ → 2H₂O + O₂

Now, the equation is balanced.

**** check ****

Element >>> Left Side >>> Right Side

H >>>>>>>>> 4 >>>>>>>>> 4

O >>>>>>>>> 4 >>>>>>>>> 4

6 0
3 years ago
Boron’s chemistry is not typical of its group.(a) Cite three ways in which boron and its compounds differ significantly from the
Mila [183]

Boron’s chemistry is not typical of its group. is group 3A (13) shows the increasing metallic character from Al to Tl.

All Boron compounds are covalent whereas the other elements in group 3A (13) form mostly ionic compounds.

Except for Boron, the other elements of group 3A (13) show increasing metallic character from Al to Tl. But Boron is a metalloid.

Compared to the other elements in group 3A, boron has a lower reactivity in chemical terms (13)

The metalloid boron (B), as well as the metals aluminium (Al), gallium (Ga), indium (In), and thallium, are all part of group 3A (or IIIA) of the periodic table (Tl). In contrast to the other members of Group 3A, the element borax primarily forms covalent connections.

To learn more about group 3A (13) refer the link:

brainly.com/question/5489194

#SPJ4

6 0
1 year ago
How many moles of sucrose (C12H22O11) would be in 8.7 L of a 1.1 M solution of sucrose?
poizon [28]

Answer:

9.57 mol.

Explanation:

<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>

<em />

<em>M = (no. of moles of solute)/(V of the solution (L)).</em>

<em></em>

∴ M = (no. of moles of sucrose)/(V of the solution (L)).

1.1 M = (no. of moles of sucrose)/(8.7 L).

<em>∴ no. of moles of sucrose = (1.1 M)(8.7 L) = 9.57 mol.</em>

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3 years ago
Lead(2) sulfate yields to lead(2)sulfite and oxygen
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A standardized test of what you want to do with your friends and you get to know what you think you want to be tre
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WHAT ARE SOME FUN ALCHSELTER EXPERIMENTS?
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You can put an egg in Vinegar  an egg in Olive oil


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