Nitrogen and hydrogen react to form ammonia according to the following equation: N2(g)+3H2(g)⇌2NH3(g) Consider the following rep
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2KClO₃ → 2KCl + 3O₂
mole ratio of KClO₃ to O₂ is 2 : 3
∴ if moles of O₂ = 5 mol
then moles of KClO₃ =
= 3.33 mol
Mass of KClO₃ needed = mol of KClO₃ × molar mass of KClO₃
= 3.33 mol × ((39 × 1) + (35.5 × 1) + (16 × 3) g/mol
= 407.93 g
mole ratio of KClO₃ to O₂ is 2 : 3
∴ if moles of O₂ = 5 mol
then moles of KClO₃ =
= 3.33 mol
Mass of KClO₃ needed = mol of KClO₃ × molar mass of KClO₃
= 3.33 mol × ((39 × 1) + (35.5 × 1) + (16 × 3) g/mol
= 407.93 g
λ=Wavelength = .129 m = 0.129 m
E = energy = ?
h =Planck constant = 6.63 × 10^-34 J.s
f = frequency of photo/ electromagnetic radiation = c/λ
c = Speed of light in a vacuum = 3 × 10^8 m/s
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