The Mercury's mass for the given acceleration due to gravity is 0.3152 x 10²⁴ kg.
The ratio of the calculated and accepted value of the Mercury's mass is 0.95.
<h3>What is mass?</h3>
Mass is the amount of matter present in the object.
The mass of the object is always constant, anywhere it is on the Earth or Moon or any other planet.
Given is the acceleration due to gravity of Mercury planet at North pole is g = 3.698 m/s² and the radius of Mercury planet is 2440 km.
The acceleration due to gravity is related with mass as
g = GM/R²
Substitute the values, we have
3.698 = 6.67 x 10⁻¹¹ x M/(2440 x1000)³
M = 2.2016 x 10¹³ / 6.67 x 10⁻¹¹
M = 0.3152 x 10²⁴ kg
Thus, the mercury's mass is 0.3152 x 10²⁴ kg.
(b) Accepted value of Mercury's mass is 3.301 x 10²³ kg
Ratio of the value of mass calculated and accepted is
Mcalc/M accep = 0.3152 x 10²⁴ kg / 3.301 x 10²³ kg
= 0.95
Thus, the ratio is 0.95
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We live on the troposphere
Answer:
Explanation:
In an ideal transformer, the ratio of the voltages is proportional to the ratio of the number of turns of the windings. In this way:
In this case:
Therefore, using the previous equation and the data provided, let's solve for 
:
Hence, the number of loops in the secondary is approximately 41667.
Answer:
time taken is equal to 14,156 years
Explanation:
we know,
at t = 0
Y(0) = A
given that half life of plutonium 239 = 24,200
hence time taken is equal to 14,156 years
Answer: only the third option. [Vector A] dot [vector B + vector C]
The dot between the vectors mean that the operation to perform is the "scalar product", alson known as "dot product".
This operation is only defined between two vectors, not one scalar and one vector.
When you perform, in the first option, the dot product of any ot the first and the second vectors you get a scalar, then you cannot make the dot product of this result with the third vector.
For the second option, when you perform the dot product of vectar B with vector C you get a scalar, then you cannot make the dot product ot this result with the vector A.
The third option indicates that you sum the vectors B and C, whose result is a vector and later you make the dot product of this resulting vector with the vector A. Operation valid.
The fourth option indicates the dot product of a scalar with the vector A, which we already explained that is not defined.
