Answer:
a)= 29.4J
b)F = 588 N
c)= 60 Kg
Explanation:
Force constant of the spring (k) = 5880 N/m
Change in length of the spring (x) = 25 - 15 = 10 cm 0.1m
This work done on the spring as it is stretched (or compressed) can be recovered. This is stored work that can be used to do work on something else by this spring. That means the stretched (or compressed) spring has energy -- potential energy. This is spring potential energy or elastic potential energy.
a) Work done in pulling the body W = 1/2kx²
= 1/2 (5880)(0.1)2
= 29.4J
b)From Hook's Law,
F = ke
Where F = applied force, k = spring constant, e = extension.
Given: k = 5880 N/m, e = 25-15 = 10 cm = 0.1 m.
Substitute into the formula above
F = 5880(0.1)
F = 588 N
c)By using the formula, F = -kx
Hence mg = kx
Thus m x 9.8 =5880 x0.1
Hence mass of the body
m= 5880 x0.1/9.8
= 60 Kg
Given info
d = 0.000250 meters = distance between slits
L = 302 cm = 0.302 meters = distance from slits to screen
= angle to 8th max (note how m = 8 since we're comparing this to the form )
(n = 5 as we're dealing with the 5th minimum )
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Method 1
Make sure your calculator is in degree mode.
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Method 2
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Method 3
There is a slight discrepancy (the first two results were 611 nm while this is roughly 613 nm) which could be a result of rounding error, but I'm not entirely sure.
Answer:
Hello your question is incomplete hence I will give you a general answer as regards to tectonic plates sliding past each other in a sideways direction
answer : The Transform boundary is been demonstrated by the students when sliding tectonic plates past each other in sideways directions
Explanation:
The event that can be demonstrated by the students using blocks to represent tectonic plates and sliding the clocks past each other in sideways direction is Transform Boundary of the tectonic plates