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sukhopar [10]
2 years ago
6

(Redoing this question because it formatted wrong)

Mathematics
1 answer:
mojhsa [17]2 years ago
7 0

Answer:

a

Step-by-step explanation:

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How do you solve this?
solong [7]

It looks like your equations are

7M - 2t = -30

5t - 12M = 115

<u>Solving by substitution</u>

Solve either equation for one variable. For example,

7M - 2t = -30   ⇒   t = (7M + 30)/2

Substitute this into the other equation and solve for M.

5 × (7M + 30)/2 - 12M = 115

5 (7M + 30) - 24M = 230

35M + 150 - 24M = 230

11M = 80

M = 80/11

Now solve for t.

t = (7 × (80/11) + 30)/2

t = (560/11 + 30)/2

t = (890/11)/2

t = 445/11

<u>Solving by elimination</u>

Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,

7M - 2t = -30   ⇒   -10t + 35M = -150 … (multiply by 5)

5t - 12M = 115   ⇒   10t - 24M = 230 … (multiply by 2)

Now combining the equations eliminates the t terms, and

(-10t + 35M) + (10t - 24M) = -150 + 230

11M = 80

M = 80/11

It follows that

7 × (80/11) - 2t = -30

560/11 - 2t = -30

2t = 890/11

t = 445/11

4 0
2 years ago
Can you solve this? It is for MATH 111
umka2103 [35]
The equation only is true for objects with negligible air resistance. A feather does not have this property.
Using the equation shown:
50 = -16t^2
t^2 = 50/16 = 3.125
t = sqrt(3.125) = 1.77 seconds
6 0
3 years ago
Find the value of S for an infinite geometric series with r= 1/6 and a1=10
Lelu [443]
S=a1/1-r=10 x 6/5 = 12
5 0
3 years ago
A van and a bicycle move towards each other. The speed of the van is 80 km per hour, and the speed of the bike is 20 km per hour
otez555 [7]

:

.

-- :

Bike > ________300km_________< Van

20km/h 80km/h

In one hour, the bike will have moved 20km and the van would have moved 80km.

The distance between them was 300km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

300km-(20km+80km) = 200km

So now the distance between them is 200km.

Now another hour passes. The distance between them was 200km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

200km-(20km+80km) = 100km

So now the distance between them is 100km

Now another hour passes. The distance between them was 100km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

100km-(20km+80km) = 0km

So now the distance between them is 0km, which means they have met. If we count, it took them 3 hours.

:

Step 1)

Add both speeds. 20km+80km=100km

Step 2)

Total distance between them = 300km

So do 300km/100km = 3hours.

______

The solution is: .

————

Hope this helped!

4 0
3 years ago
The miniature gold scores for 7 friends are 23, 30, 32, 35, 14, and 23. What is the mean golf score for this group of friends ?
Andrej [43]

If you add them all together, you'd get 157. Then you divide by 7 and you'd get 31.4

6 0
3 years ago
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