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kompoz [17]
2 years ago
15

PLEASE HELP!!!! IT'S DUE TODAY!!!

Chemistry
2 answers:
Dafna1 [17]2 years ago
7 0
I’m pretty sure the answer is B
Hope this helps
LuckyWell [14K]2 years ago
5 0

Answer:

I think it might be C

Explanation:

Im not sure though

Please tell me if im wrong

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Select the correct answer<br><br> Giving brainliest
ANEK [815]

Answer:

it is the bowling ball is the correct one

6 0
3 years ago
Two separate masses of zinc were measured on a laboratory balance. The first zinc had a sample mass of 210.10g, and the second z
wlad13 [49]

Answer:

Density is  7.15 g /mL.

Mass is  445.2 g.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Mass of first zinc sample = 210.10 g

Mass of second zinc sample = 235.10 g

Combined volume = 62.3 mL

Density of combined sample ?

Mass of combined sample = ?

Solution:

Mass of combined sample = 210.10 g + 235.10 g = 445.2 g

density = mass / volume

density = 445.2 g / 62.3 mL

density = 7.15 g /mL

3 0
3 years ago
The temperature of a container of oxygen gas is increased from 149 k to 298 k which of the following statement is true
ozzi

Answer:

______is used in production of hard disk.

Explanation:

8 0
3 years ago
PLEASE HELP WILL RATE THE BRAINLIEST
erastovalidia [21]

The Plum Pudding model of the atom was like a  modernchocolate chip cookie it had subatomic particles embedded inside it in no particular arrangement

the gold foil experiment proved that there was a lot of empty space in an atom Because of the launched Particles.mostly deflected but some went through the foil  

4 0
3 years ago
Give the oxidation state of the metal species in each complex. ru(cn)(co)4 -
kogti [31]
The given complex ion is as follow,

                                              [Ru (CN) (CO)₄]⁻

Where;
            [ ]  =  Coordination Sphere

            Ru  =  Central Metal Atom  =  <span>Ruthenium

            CN  =  Cyanide Ligand

            CO  =  Carbonyl Ligand

The charge on Ru is calculated as follow,

                               Ru + (CN) + (CO)</span>₄  =  -1
Where;
            -1  =  overall charge on sphere

             0  =  Charge on neutral CO

            -1  =  Charge on CN

So, Putting values,


                               Ru + (-1) + (0)₄  =  -1

                               Ru - 1 + 0  =  -1

                               Ru - 1  =  -1

                               Ru  =  -1 + 1

                               Ru  =  0
Result:
          <span>Oxidation state of the metal species in each complex [Ru(CN)(CO)</span>₄]⁻ is zero.
3 0
3 years ago
Read 2 more answers
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