Hurry I need the answer asap

Which property determine am atoms ability to attract electrons shared in a chemical bond?

brilliants [131]

Hello there!

Electronegativity is what determine's an atoms ability to attract electrons shared in a chemical bond.Ionization, atomic radius, and also ionic radius both would not determine this as they wouldn't have any similar bond that would attract.

Your correct answer would be (option c)

A. ionization

B. atomic radius

C. electronegativity

D. ionic radius

I hope this helps you!

8 0

3 years ago

How many moles of NaOH are in 27.8 mL of 0.168 M NaOH?

Alex17521 [72]

Your answer would be 0.00285 moles.

8 0

3 years ago

Need help with this ASAP Thanks!

olga_2 [115]

Answer:

Decomposers (either Secondary Consumer or Tertiary Consumer)

Explanation:

Decomposers eat dead materials and break them down into chemical parts. ... They keep the ecosystem free of the bodies of dead animals or carrion. They break down the organic material and recycle it into the ecosystem as nutrients. Vultures, Blowflies, hyenas, crabs, lobsters and eels are examples of scavengers.

6 0

3 years ago

A gold coin contains 3.47 × 10^23 gold atoms. What is the mass of the coin in grams?

VashaNatasha [74]

Answer:

Mass = 114.26 g

Explanation:

Given data:

Number of gold atoms = 3.47×10²³ atoms

Mass in gram = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

3.47×10²³ atoms × 1 mol /6.022 × 10²³ atoms

0.58 mol

Mass of gold:

Mass = number of moles × molar mass

Mass = 0.58 mol × 197 g/mol

Mass = 114.26 g

4 0

3 years ago

You are given a solution that is 518 mM lactose. You need to make up 4.5 L of 16.7 mM solution. What volume do you need to trans

OLga [1]

Answer:

The volume you need to transfer from the stock solution is 0.145 l

Explanation:

Since the number of moles of lactose in the volume of stock solution that you transfer will be the same as the number of moles of lactose in the final solution, you can use this expression:

number of moles in volume to transfer = number of moles in the final solution

Since number of moles = concentration * volume (if the concentration is expressed in molarity), then:

Ci * Vi = Cf * Vf

where:

Ci = concentration of the stock solution.

Vi = volume of the stock solution to be transferred.

Cf = concentration of the final solution

Vf = volume of the final solution

Then, replacing with the data:

518 mM * Vi = 16.7 mM * 4.5 l

Vi = 16.7 mM * 4.5 l / 518 mM

Vi = 0.145 l or 145 ml

Notice that any concentration unit can be used, as long as the units of the concentration of the stock and final solution are the same.

4 0

3 years ago