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kykrilka [37]
3 years ago
11

Hurry I need the answer asap

Chemistry
1 answer:
Llana [10]3 years ago
4 0

Answer:

The image represents liquid

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If 4.50 g of (nh4)2so4 is dissolved in enough water to form 250. ml of solution, what is the molarity of the solution?
natima [27]
The molarity of a solution is the number of moles of a substance in one liter of that substance. 
The molar mass of ammonium sulfate (NH4)2SO4 is 132.14 grams/mole
Calculate the moles of ammonium sulfate:
(4.50 grams)/(132.14 grams/mole) = 0.0341 moles of ammonium sulfate
convert mL to Liters 250. mL becomes 0.250 liters
Take the number of moles over the number of liters
0.0341 moles / 0.250 liters = 0.136 molar or 0.136M = molarity of the solution
8 0
3 years ago
How to write a compound that contains one aluminum atom for every three chlorine atoms?
devlian [24]
AlCl₃
.............
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4 0
3 years ago
Which gas is produced when dilute hydrochloric acid is added to a reactive metal.
Digiron [165]

Hydrogen gas is produced when dilute hydrochloric acid is added to a reactive metal.

Balanced molecular equation of sodim metal with hydrochloric acid:

2Na(s) + 2HCl(aq) → 2NaCl(aq) + H₂(g).

Ionic equation: 2Na(s) + 2H⁺(aq) + 2Cl⁻(aq) → 2Na⁺ + 2Cl⁻(aq) + H₂(g).

Net ionic equation: 2Na(s) + 2H⁺(aq) → 2Na⁺(aq) + H₂(g).

Sodium is oxidized from oxidation number 0 (Na) to oxidation number +1, hydrogen is reduced from oxidation number +1 to oxidation number 0 (hydrogen gas H₂).

Another example:

Balanced chemical equation: Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

Word equation: zinc + hydrochloric acid → zinc chloride + hydrogen gas

More about hydrogen gas:brainly.com/question/24433860

#SPJ4

7 0
1 year ago
Gaseous hydrogen iodide is placed in a closed container at 425∘C, where it partially decomposes to hydrogen and iodine: 2HI(g)⇌H
murzikaleks [220]

Answer:

0.0184

Explanation:

Let's consider the following reaction at equilibrium.

2 HI(g) ⇌ H₂(g) + I₂(g)

The concentration equilibrium constant (Kc) is equal to the product of the concentration of the products raised to their  stoichiometric coefficients divided by the product of the concentration of the reactants raised to their  stoichiometric coefficients.

Kc = [H₂] × [I₂] / [HI]²

Kc = (4.78 × 10⁻⁴) × (4.78 × 10⁻⁴) / (3.52 × 10⁻³)²

Kc = 0.0184

5 0
3 years ago
At equilibrium the partial pressures of N2O4 and NO2 are 0.35 atm and 4.3 atm. What is the Kp
ale4655 [162]

Answer:

Kp = 52.83

Explanation:

6 0
3 years ago
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