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Luba_88 [7]
3 years ago
10

Help for brainlist and extra points!!

Chemistry
1 answer:
Ratling [72]3 years ago
7 0

Answer:

Explanation:

c.

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A gas occupies 3.5L at 2.5 atm of pressure. What is the volume at 787 torr at the same temperature?
Kitty [74]

Answer: 8.45 L

Explanation:

Given that,

Initial volume (V1) = 3.5L

Initial pressure (P1) = 2.5 atm

[Since final pressure is given in torr, convert 2.5 atm to torr

If 1 atm = 760 torr

2.5 atm = 2.5 x 760 = 1900 torr

Final volume (V2) = ?

Final pressure (P2) = 787 torr

Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law

P1V1 = P2V2

3.5L x 1900 torr = 787 torr x V2

6650L•torr = 787 torr•V2

Divide both sides by 787 torr

6650L•torr/787 torr = 787 torr•V2/787 torr

8.45 L = V2

Thus, the volume of the gas at 787 torr and at the same temperature is 8.45 Liters

5 0
3 years ago
How do you view failure? Is failure the end, or is failure an important lesson and motivator?
Katyanochek1 [597]

Answer:

Failure is a lesson

Explanation:

Without failure, we'd be less capable of compassion, empathy, kindness, and great achievement. It's through failure that we learn the greatest lessons that life could teach us.

8 0
3 years ago
What is the entropy change of the surroundings
KiRa [710]

Answer: The entropy change of the surroundings will be -17.7 J/K mol.

Explanation: The enthalpy of vapourization for 1 mole of acetone is 31.3 kJ/mol

Amount of Acetone given = 10.8 g

Number of moles is calculated by using the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of acetone = 58 g/mol

Number of moles = \frac{10.8}{58}=0.1862moles

If 1 mole of acetone has 32.3 kJ/mol of enthalpy, then

0.1862 moles will have = \frac{32.3}{1}\times 0.1862=5.828kJ/mol

To calculate the entropy change for the system, we use the formula:

\Delta S_{sys}=\frac{\Delta H_{vap}}{T(\text{ in K)}}

Temperature = 56.2°C = (273 + 56.2)K = 329.2K

Putting values in above equation, we get

\Delta S_{sys}=\frac{5.828}{329.2}=0.0177kJ/Kmol=17.7J/Kmol   (Conversion Factor: 1 kJ = 1000J)

At Boiling point, the liquid phase and gaseous phase of acetone are in equilibrium. Hence,

\Delta S_{system}+\Delta S_{surrounding}=0

\Delta S_{surrouding}=-\Delta S_{system}=-17.7J/Kmol

5 0
3 years ago
What are three types of subatomic particles
saw5 [17]

protons, neutrons, and electrons.

8 0
3 years ago
Estimate the number of moles of water in all the Earth's oceans. Assume water covers 75% of the Earth to an average depth of 3 k
o-na [289]

Answer:

there are approximately n ≈ 10²² moles

Explanation:

Since the radius of the earth is approximately R=6378 km= 6.378*10⁶ m , then the surface S of the earth would be

S= 4*π*R²

since the water covers 75% of the Earth's surface , the surface covered by water Sw is

Sw=0.75*S

the volume for a surface Sw and a depth D= 3 km = 3000 m ( approximating the volume through a rectangular shape) is

V=Sw*D

the mass of water under a volume V , assuming a density ρ= 1000 kg/m³ is

m=ρ*V

the number of moles n of water ( molecular weight M= 18 g/mole = 1.8*10⁻² kg/mole ) for a mass m is

n = m/M

then

n = m/M = ρ*V/M = ρ*Sw*D/M = 0.75*ρ*S*D/M = 3/4*ρ*4*π*R² *D/M = 3*π*ρ*R² *D/M

n=3*π*ρ*R² *D/M

replacing values

n=3*π*ρ*R² *D/M = 3*π*1000 kg/m³*(6.378*10⁶ m)² *3000 m /(1.8*10⁻² kg/mole) = 3*π*6.378*3/1.8 * 10²⁰ = 100.18 * 10²⁰ ≈ 10²² moles

n ≈ 10²² moles

8 0
3 years ago
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