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Naddik [55]
3 years ago
12

Explain how you would convert the moles of a compound to the made (grams) of the same compound​

Chemistry
1 answer:
Oduvanchick [21]3 years ago
3 0

Answer:

see notes below

Explanation:

The mole is the mass of substance containing 1 Avogadro's Number of particles. That is, 1 mole substance = 1 formula weight. For elements, 1 mole weight is equal to the atomic weight expressed as grams. For molecules, 1 mole weight is equal to the molecular weight expressed as grams.

1 mole = 1 formula weight

<u>Moles to Grams and Grams to Moles</u>

Grams => Moles

Given grams, moles = mass given / formula weight

*Ask the question => How many formula weights are there in the given mass? => Results is always moles.

Moles => Grams

Given moles,  grams = moles given X formula weight

*Summary

Grams to Moles => divide by formula weight

Moles to Grams => multiply by formula weight

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C and D are wrong. Coal and natural gas are not biomass fuels.

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How does sand cause weathering?
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What type of bond will form between nitrogen and bromine?
madreJ [45]

Answer:

Non-polar covalent bond

Explanation:

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2 years ago
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Consider the titration of 30.0 mL of 0.050 M NH3 with 0.025 M HCl.
Alla [95]

Answer:

60.0mL

Explanation:

For the process of titration , the formula we use is -

M₁V₁ = M₂V₂

Where ,

M₁ = initial concentration

V₁ = initial volume

M₂ = final concentration

V₂ = final volume .

Hence , from the question ,

The given data is ,

M₁ = 0.050 M

V₁ = 30.0mL

M₂ = 0.025 M

V₂ = ?

Now, to determine the unknown quantity , the formula can be applied ,

Hence ,

M₁V₁ = M₂V₂

Putting the respective values ,

0.050 M * 30.0mL = 0.025 M * ?

solving the above equation ,

V₂ = ? = 60.0mL

6 0
3 years ago
The solubility of a gas is 0.890 g/L at a pressure of 120 kPa. What is the solubility of the gas if the pressure is changed to 1
IgorC [24]

The solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

<h3>Effect of Pressure on Solubility </h3>

As the <em>pressure </em>of a gas increases, the <em>solubility </em>increases, and as the <em>pressure </em>of a gas decreases, the <em>solubility </em>decreases.

Thus, Solubility varies directly with Pressure

If S represents Solubility and P represents Pressure,

Then we can write that

S ∝ P

Introducing proportionality constant, k

S = kP

S/P = k

∴ We can write that

\frac{S_{1} }{P_{1} } = \frac{S_{2} }{P_{2} }

Where S_{1} is the initial solubility

P_{1} is the initial pressure

S_{2} is the final solubility

P_{2} is the final pressure

From the given information

S_{1} = 0.890 \ g/L

P_{1} = 120 \ kPa

P_{2} = 100 \ kPa

Putting the parameters into the formula, we get

\frac{0.890}{120}=\frac{S_{2}}{100}

S_{2}= \frac{0.890 \times 100}{120}

S_{2}= 0.742 \ g/L

Hence, the solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

Learn more on Solubility here: brainly.com/question/4529762

7 0
2 years ago
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