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Juli2301 [7.4K]
2 years ago
12

In a 7 horse field what is a box trifecta

Mathematics
2 answers:
natali 33 [55]2 years ago
3 0

Trifecta Box Costs:

$1 Trifecta Box with three horses $6 (6 possible combinations)

$1 Trifecta Box with five horses $60 (60 possible combinations)

$1 Trifecta Box with six horses $120 (120 possible combinations)

$1 Trifecta Box with seven horses $210 (210 possible combinations)

Ulleksa [173]2 years ago
3 0

Answer:

$1 Trifecta Box with seven horses $210 (210 possible combinations)

Step-by-step explanation:

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What is the area of the triangle?​
Tpy6a [65]

Answer:

20.25

Step-by-step explanation:

To find the area of a triangle you do base x height/2

9x4.5/2

40.5/2= 20.25

8 0
3 years ago
The probability of that nicky will pass his driving test is 3/7 what is the probability of him failing?
erastovalidia [21]

Answer:

4/7

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Plz help.. plzz if you can
Mazyrski [523]

Answer:

C is a function

Step-by-step explanation:

We can use the vertical line test.  If a vertical straight lines passes through the graph more than one, it is not a function

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C is a function

5 0
2 years ago
A rectangle has an area of 48
nika2105 [10]
Answer: i didnt understand the answer choice but the correct answer is 48/12=width. width=4

Step-by-step explanation:
as we know the area of a rectangle is area=length X width
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6 0
2 years ago
assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28
melomori [17]

Given:

x and y are both differentiable functions of t.

4x^2+3y^3=28

x=-1\text{ and }\dfrac{dy}{dt}=8

To find:

The value of \dfrac{dx}{dt}.

Solution:

We have,

4x^2+3y^3=28       ...(i)

At x=-1,

4(-1)^2+3y^3=28

4+3y^3=28

3y^3=28-4

3y^3=24

Divide both sides by 3.

y^3=8

Taking cube root on both sides.

y=2

So, y=2 at x=-1.

Differentiate (i) with respect to t.

4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0

Putting x=-1, y=2 and \dfrac{dy}{dt}=8, we get

4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0

-8\dfrac{dx}{dt}+9(4)(8)=0

-8(\dfrac{dx}{dt}-9(4))=0

Divide both sides by -8.

\dfrac{dx}{dt}-36=0

\dfrac{dx}{dt}=36

Therefore, the value of 4x^2+3y^3=28 is 36.

6 0
2 years ago
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