Question

How much 10,000J will raise the temperature of 1 liter of water in C

Answer 1

10,000J will raise the temperature of 1 liter of water by 2.38 °C

Using Q = mcΔT where Q = quantity of heat supplied = 10000 J,

m = mass of 1 liter of water = ρV where ρ = density of water = 1000 kg/m³ and V = volume of water = 1 liter = 1 dm³ = 1 × 10⁻³ m³.

So, m = ρV = 1000 kg/m³ × 1 × 10⁻³ m³ = 1 kg,

c = specific heat capacity of water = 4200 J/kg°C and ΔT = temperature change.

Making ΔT subject of the formula, we have

ΔT = Q/mc

Substituting the values of the variables into the equation, we have

ΔT = Q/mc

ΔT = 10000 J/(1 kg × 4200 J/kg°C)

ΔT = 10000 J/(4200 J/°C)

ΔT = 2.38 °C

So, 10,000J will raise the temperature of 1 liter of water by 2.38 °C

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