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3 years ago

What happens to the air pressure as you go higher in the atmosphere?

Chemistry

1 answer:

grigory [225]3 years ago

8 0

Answer: As altitude rises, air pressure drops.

Explanation: As altitude increases, the amount of gas molecules in the air decreases—the air becomes less dense than air nearer to sea level.

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A substance that can be broken down and recycled by bacteria and other decomposes is said to be__________

Stells [14]

Answer:The substance is Biodegradable

Explanation:

When something is biodegradable it can be broken down by organical processes or decomposers.

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3 years ago

Why do ocean waves make a good source of energy?

JulsSmile [24]

Answer:

Ocean waves contain tremendous energy potential. Wave power devices extract energy directly from the surface motion of ocean waves. In many areas of the world, the wind blows with enough consistency and force to provide continuous waves along the shoreline.

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3 years ago

How to do an equation

pav-90 [236]

What do you mean by that Oh wait do you mean like 2×2=4 or 2+2=4 something like that maby?? I am still confused?? XD

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3 years ago

Which of these space missions visited the moon several times?

sesenic [268]

Answer:

Voyager 1

Explanation:

Voyager 1 is a space probe launched by NASA on September 5, 1977. Part of the Voyager program to study the outer Solar System, Voyager 1 was launched 16 days after its twin, Voyager 2

3 0

3 years ago

Read 2 more answers

Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou

Ulleksa [173]

Answer:

$4.36~g~XY$

Explanation:

In this case, we can start with the reaction:

$2X + Y_2~->~2XY$

If we check the reaction, we will have 2 X and Y atoms on both sides. So, the reaction is balanced. Now, the problem give to us two amounts of reagents. Therefore, we have to find the limiting reagent. The first step then is to find the moles of each compound using the molar mass:

$3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X$

$4.2~g~Y_2\frac{1~mol~Y_2}{48~g~Y_2}=0.0875~mol~Y_2$

Now, we can divide by the coefficient of each compound (given by the balanced reaction):

$\frac{0.04~mol~X}{1}=~0.04$

$\frac{0.0875~mol~Y_2}{2}=0.04375$

The smallest value is for "X", therefore this is our limiting reagent. Now, if we use the molar ratio between "X" and "XY" we can calculate the moles of XY, so:

$0.04~mol~X\frac{2~mol~XY}{2~mol~X}=0.04~mol~XY$

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol $Y_2$ = 48 g $Y_2$ (therefore 1 mol Y = 24 g Y). With this in mind the molar mass of XY would be 85+24 = 109 g/mol. With this in mind:

$0.04~mol~XY\frac{109~g~XY}{1~mol~XY}=4.36~g~XY$

I hope it helps!

6 0

3 years ago