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mel-nik [20]
3 years ago
5

1 point

Physics
1 answer:
Anettt [7]3 years ago
6 0

Answer:

6 hours

Explanation:

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A box is at rest on an inclined surface. Which diagram correctly illustrates all forces, including any component forces?
Brrunno [24]

Answer:

The answer is D.

Explanation:

3 0
3 years ago
Write a hypothesis about how the height of the cylinder affects the temperature of the water. Use the "if . . . then . . . becau
AnnyKZ [126]
The statement that can be used to answer this  question is:

"If the cylinder is brought higher then, its temperature when brought down becomes higher because a greater amount of potential energy is converted to thermal energy."

The potential energy is converted to thermal energy when the object is released the velocity becomes higher because of the acceleration due to gravity.
8 0
4 years ago
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The higher u hold something above the ground? A. The less potential B. The more kinetic energy it has C. The more potential ener
fredd [130]
I think is B or C

maby is C


6 0
4 years ago
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The speed of a certain proton is 350 km/s. If the uncertainty in its momentum is 0.100%, what is the necessary uncertainty in it
Evgesh-ka [11]

Answer:

\Delta x = 1.807 \times 10^{-10}m

Explanation:

mass of proton, m = 1.67 x 10^-27 kg

speed of proton, v = 350 km/s = 350,000 m/s

Momentum of proton, p = mass x speed

p =  1.67 x 10^-27 x 350000 = 5.845 x 10^-22 kg m /s

uncertainty in momentum, Δp = 0.1 % of p

Δp = \frac{0.1\times 5.845 \times 10^{-22}}{100}=5.845 \times 10^{-25}

According to the principle

\Delta x\times \Delta p \geq  \frac{h}{2\pi }

where, Δx be the uncertainty in position

\Delta x\times 5.845 \times 10^{-25}=  \frac{6.634 \times 10^{-34}}{2\times 3.14}

\Delta x = 1.807 \times 10^{-10}m

5 0
3 years ago
Three point charges, -4.7 x 10-9 C, -9.7 x 10-9 C, and 7.2 x 10-9 C, are fixed at different positions on a circle. The total ele
irinina [24]

Answer:

Explanation:

q1 = - 4.7 x 10^-9 C

q2 = - 9.7 x 10^-9 C

q3 = 7.2 x 10^-9 C

Potential at the centre of the circle, V = - 1900 V

Let the radius of the circle is r.

So, the potential is given by

V = \frac{Kq_{1}}{r}+\frac{Kq_{2}}{r}+\frac{Kq_{3}}{r}

- 1900 = \frac{9\times 10^{9}}{r}\left ( - 4.7 - 9.7 + 7.2 \right )\times 10^{-9}

- 1900 = \frac{-9\times 7.2}{r}

r = 0.034 m = 3.4 cm

6 0
3 years ago
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