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Likurg_2 [28]
3 years ago
11

What are the potential hazards relating to materials handling injuries?

Engineering
1 answer:
const2013 [10]3 years ago
5 0

all 4 apply all these are saftey hazards and must be taken as such anything in a work enviorment should be taken seriously and such as hazard

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What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 1.9 × 10
Fiesta28 [93]

Answer:

Recall the formula for the maximum stress, σₐ = 2σ₀ *√ (α/ρₓ)

where

σ₀ = tensile stress = 140 MPa = 1.40x 10⁸Pa

α = crack length = 3.8 × 10–2 mm = 3.8 x 10⁻⁵m

ρₓ = radius of curvature = 1.9 × 10⁻⁴mm = 1.9 × 10⁻⁷m

Substituting these values into the formula, we can calculate the max stress as

 ====== 2 x 1.40x 10⁸ x √(3.8 x 10⁻⁵/1.9 × 10⁻⁷)

σₐ  = 24.4MPa

6 0
3 years ago
How does the invention of electrical lights and automobiles impact the world today? Explain. (1 paragraph minimum)
Pachacha [2.7K]

Answer:

Obviously without electrical lights and automobiles the worlds is gonna be a more difficult place to stay oweing to the fact that transportation would have a mammoth task. and when the day is gone movement would be though. due to limited light supply and no vehicles to even move.

6 0
4 years ago
Concerning the storage battery, what category of the primary sources is voltage produced?​
Natalija [7]

The primary source of voltage for a storage battery is; Active Source

<h3>What is Voltage?</h3>

Voltage is defined as the pressure from an electrical circuit's power source that pushes charged current electrons through a conducting loop, that enables them to do work such as illuminating a light.

Now, there are two primary sources of voltage which are namely active sources and passive sources.

The Active sources delivers power or energy to the circuit while the Passive sources utilizes power or energy from the circuit.

Thus, the storage battery will be an active source

Read more about Voltage at; brainly.com/question/14883923

6 0
2 years ago
A closed system of mass 10 kg undergoes a process during which there is energy transfer by work from the system of 0.147 kJ per
mr_godi [17]

Answer:

-50.005 KJ

Explanation:

Mass flow rate = 0.147 KJ per kg

mass= 10 kg

Δh= 50 m

Δv= 15 m/s

W= 10×0.147= 1.47 KJ

Δu= -5 kJ/kg

ΔKE + ΔPE+ ΔU= Q-W

0.5×m×(30^2- 15^2)+ mgΔh+mΔu= Q-W

Q= W+ 0.5×m×(30^2- 15^2) +mgΔh+mΔu

= 1.47 +0.5×1/100×(30^2- 15^2)-9.7×50/1000-50

= 1.47 +3.375-4.8450-50

Q=-50.005 KJ

7 0
4 years ago
Read 2 more answers
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allochka39001 [22]
More information is needed
3 0
4 years ago
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