A gas refrigeration system using air as the working fluid has a pressure ratio of 5. Air enters the compressor at 0°C. The high-
pressure air is cooled to 35°C by rejecting heat to the surroundings. The refrigerant leaves the turbine at −80°C and then it absorbs heat from the refrigerated space before entering the regenerator. The mass flow rate of air is 0.4 kg/s. Assuming isentropic efficiencies of 80 percent for the compressor and 85 percent for the turbine and using constant specific heats at room temperature, determine (a) the effectiveness of the regenerator, (b) the rate of heat removal from
1 answer:
Answer:
(a) Effectiveness of the regenerator= 0.433
(b) The rate of heat removal=21.38 kW
Explanation:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
You might be interested in
Answer:
A) complex power = apparent power = ( 108.253 + 62.5 i ) VA
active power = 108.25 watts
reactive power = 62.5 VAR'S
power factor = cos ∅ = cos 30° = 0.866 ( lagging )
also ; current lags voltage by 30°
B) your question is not well written hence no answer
Explanation:
A) v(t) = 100 cos (377t - 30° ) v
Vrms = ∠ -30°
I(t) = 2.5cos(377t- 60°) A
Irms = ∠ -60°
determine complex power apparent power . ...... power factor
Note : complex power = apparent power
=( Irms ) * Vrms
= ( ∠ -60° ) * (
∠ -30° )
= 125 ∠ 30°
= ( 108.253 + 62.5 i ) VA ( complex power )
active power = 108.25 watts
reactive power = 62.5 VAR'S
power factor = cos ∅ = cos 30° = 0.866 ( lagging )
current lags voltage by 30°