Y = a (b)^t/p
y is total money
a is original amount
b is growth / decay factor
t is time
p is the frequency of every growth or decay
15131.76 = 11613 x 1.08^x
15131.76 / 11613 = 1.08^x
1.303… = 1.08^x
log1.303…. = xlog1.08
x = 3.43902165741 years
Anything greater than total vacuum is technically a form of pressure
Question:
The question is not complete. See the complete question and the answer below.
A well that pumps at a constant rate of 0.5m3/s fully penetrates a confined aquifer of 34 m thickness. After a long period of pumping, near steady state conditions, the measured drawdowns at two observation wells 50m and 100m from the pumping well are 0.9 and 0.4 m respectively. (a) Calculate the hydraulic conductivity and transmissivity of the aquifer (b) estimate the radius of influence of the pumping well, and (c) calculate the expected drawdown in the pumping well if the radius of the well is 0.4m.
Answer:
T = 0.11029m²/sec
Radius of influence = 93.304m
expected drawdown = 3.9336m
Explanation:
See the attached file for the explanation.
Answer:
We can describe 15×-10 as an expression. we would describe 6×-2< 35 as an...
Explanation:
We can describe 15×-10 as an expression. we would describe 6×-2< 35 as an...
Answer:
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Explanation:
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