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vazorg [7]
3 years ago
11

5. Consider two glasses, one filled with water and the other half-full, with the water in the two glasses being at the same temp

erature. In which glass are the water molecules moving faster? In which is there greater internal energy? In which will more heat be required to increase the temperature by 1 degree C?
Physics
1 answer:
ratelena [41]3 years ago
6 0

Answer:

Explanation:

In the glass full of water, volume and therefore mass of water is more than that in  glass, half filled with water. Temperature of water is same . The velocity of molecules depend on the temperature of the material. Since temperature of water is same in both the glasses, the velocity of water molecules will be same in both the glasses.

. The internal energy per unit volume or mass  too is dependent on the temperature . Since the volume of water is more in the fully filled glass , internal energy too will be more of this glass.

Heat required to increase unit degree temperature of unit mass of any thing is called specific heat . In case of water one calorie of heat is required to increase temperature by  one degree C in mass of  one gram of water .Since,  gram of water is more in case of fully filled glass , more heat will be required to increase the temperature by one  degree C of water in fully filled glass.

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Answer:

Boiling point of water is 100 deg C. It takes about 540 cal to change 1 g of water at the boiling point to 1 g of steam at 100 deg C.

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2 years ago
The particle in the atom with a negative charge is the ______<br> Answer here
NISA [10]

Answer:

Explanation:

The electron has a negative charge. Proton is positive and neutron is neutral.

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3 years ago
Read 2 more answers
A 3.35 kg object initially moving in the positive x direction with a velocity of 4.90 m s collides with and sticks to a 1.88 kg
ahrayia [7]

Answer:

The final components of velocity of the composite object is 3.33 m/s.

Explanation:

Given;

mass of the first object, m₁ = 3.35 kg

initial velocity of the first object, u₁ = 4.90 m/s in positive x-direction

mass of the second object, m₂ = 1.88 kg

initial velocity of the second object, u₂ = 3.12 m/s in negative y-direction

initial momentum of the first object, P₁ = 3.35 x 4.9 = 16.415 kgm/s

initial momentum of the second object, P₂ = 1.88 x 3.12 = 5.8656 kgm/s

The resultant velocity of the two objects is given by;

R² = 16.415² + 5.8656²

R² = 303.858

R = √303.858

R = 17.432 kgm/s

Apply the principle of conservation of linear momentum for inelastic collision;

total initial momentum before = total final momentum after collision

P₁(x) + P₂(y) = Pf

R = Pf

R = v(m₁ + m₂)

17.432 = v(m₁ + m₂)

where;

v is the final components of velocity of the composite object

v = \frac{17.432}{m_1 + m_2} \\\\v = \frac{17.432}{3.35+1.88} \\\\v = 3.33 \ m/s

Therefore, the final components of velocity of the composite object is 3.33 m/s.

8 0
2 years ago
Am arrow of mass 1000kg is shot into a wooden block of mass 5000lg lying at rest in a smooth surface.If the arrow travels 15m/s
Ber [7]

Answer:

Vf=3

Explanation:

you must first write your data

data before impact

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data after impact

M1=1000 M2=5000

V1=15m/s V2=?

M1V1 +M2V2=M1V1 +M2V2f

(1000)(0)+(5000)(0)=(1000)(15)+(5000)Vf

0=15000+5000Vf

- 15000÷5000=5000Vf÷5000

Vf= -3

Vf =3

6 0
2 years ago
Please solve this question ​
lesantik [10]

Answer:

88200 Pa

it is because

height =9m

density=1000kg/m(cube)

gravity = 9.8m/s(square)

now,

P=d×g×h

= 1000×9.8×9

=88200pa

8 0
2 years ago
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