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vazorg [7]
4 years ago
11

5. Consider two glasses, one filled with water and the other half-full, with the water in the two glasses being at the same temp

erature. In which glass are the water molecules moving faster? In which is there greater internal energy? In which will more heat be required to increase the temperature by 1 degree C?
Physics
1 answer:
ratelena [41]4 years ago
6 0

Answer:

Explanation:

In the glass full of water, volume and therefore mass of water is more than that in  glass, half filled with water. Temperature of water is same . The velocity of molecules depend on the temperature of the material. Since temperature of water is same in both the glasses, the velocity of water molecules will be same in both the glasses.

. The internal energy per unit volume or mass  too is dependent on the temperature . Since the volume of water is more in the fully filled glass , internal energy too will be more of this glass.

Heat required to increase unit degree temperature of unit mass of any thing is called specific heat . In case of water one calorie of heat is required to increase temperature by  one degree C in mass of  one gram of water .Since,  gram of water is more in case of fully filled glass , more heat will be required to increase the temperature by one  degree C of water in fully filled glass.

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(a)

The expression for the impedance is as follows:

Z=\frac{V_rms}{I_rms}

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Z=\frac{110}{0.600}

Z=183.33\Omega

Therefore, the impedance in the circuit is Z=183.33\Omega.

(b)

The expression for the average power is as follows;

P_{a}=I_{rms}^{2}R

Here, P_{a} is the average power and R is the resistance.

Calculate the resistance by rearranging the above expression.

R=\frac{P_{a}}{I_{rms}^{2}}

Put P_{a}=14W and

R=\frac{14}{{0.600}^{2}}

R=38.89\Omega

Therefore, the resistance is R=38.89\Omega.

(c)

The expression for the impedance is as follows;

Z^{2}=R^{2}+X_{L}^{2}

Here,X_{L} is the inductive reactance.

Put Z=183.33\Omega and R=38.89\Omega.

(183.33)^{2}=(38.89)^{2}+X_{L}^{2}

X_{L}=179.16\Omega

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X_{L}=2\pi fL

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L=\frac{X_{L}}{2\pi f}

Put X_{L}=179.16\Omega and f=50Hz.

L=\frac{179.16}{2\pi (50)}

L=0.57 H

Therefore, the inuctance is 0.57 H.

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