"This resolving power" was obviously stated earlier, somewhere before the point where you started copying. With no resolving power specified, there's actually no question, and so no answer.
Answer:
(a) 7 m
(b) 1 m
Explanation:
Given:
The magnitude of displacement vector 'a' is 3 m
The magnitude of displacement vector 'b' is 4 m.
The vector 'c' is the vector sum of vectors 'a' and 'b'.
(a)
Now, when the angle between the vectors is 0°, it means that the vectors are in the same direction. When vectors are in the same direction, then their resultant magnitude is simply the sum of their magnitudes.
So, magnitude of 'c' when 'a' and 'b' are in same direction is given as:
![|\overrightarrow c|=|\overrightarrow a|+|\overrightarrow b|\\\\|\overrightarrow c|=3 + 4 = 7\ m](https://tex.z-dn.net/?f=%7C%5Coverrightarrow%20c%7C%3D%7C%5Coverrightarrow%20a%7C%2B%7C%5Coverrightarrow%20b%7C%5C%5C%5C%5C%7C%5Coverrightarrow%20c%7C%3D3%20%2B%204%20%3D%207%5C%20m)
Therefore, the magnitude of vector 'c' is 7 m when angle between 'a' and 'b' is 0°.
(b)
When the angle between the vectors is 180°, it means that the vectors are exactly in the opposite direction. When the vectors are in opposite direction, then their resultant magnitude is the subtraction of their magnitudes.
So, magnitude of 'c' when 'a' and 'b' are in opposite direction is:
![|\overrightarrow c|=||\overrightarrow a|-|\overrightarrow b||\\\\|\overrightarrow c|=|3 - 4| = 1\ m](https://tex.z-dn.net/?f=%7C%5Coverrightarrow%20c%7C%3D%7C%7C%5Coverrightarrow%20a%7C-%7C%5Coverrightarrow%20b%7C%7C%5C%5C%5C%5C%7C%5Coverrightarrow%20c%7C%3D%7C3%20-%204%7C%20%3D%201%5C%20m)
Therefore, the magnitude of vector 'c' is 1 m when angle between 'a' and 'b' is 180°.
During freezing, energy is released by the mass of water without change in temperature. Such energy will also be required if the same mass of water has to be melted.
Then,
Number of moles = mass/molar mass = 253/18.02 =14.04 moles
Energy released = moles*molar enthalpy of fusion = 14.04*6.008 = 84.35 kJ
Explanation:
A pilot flying a weight; it takes t = 3.4 s to hit the ground, during which it travels a horizontal distance d = 120 m
h = g/2*t^2
h= 4.903*3.4^2
h=56.701 m
V = d/t
V= 120/3.4
V=35.3 m/sec
Now the pilot does a run at the same height but twice the speed.
How much time (t1) does it take the weight to hit the ground?
t1 = t = 3.4 sec (depending just upon height)