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Elanso [62]
3 years ago
9

How much is one degree Celsius in temperature change ?

Physics
1 answer:
Aleks04 [339]3 years ago
6 0
33.8 Fahrenheit is the change of 1 degree

 

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What happens to waves energy when it’s absorbed by an median
Ipatiy [6.2K]

Answer:

Absorption, in wave motion, the transfer of the energy of a wave to matter as the wave passes through it. The energy of an acoustic, electromagnetic, or other wave is proportional to the square of its amplitude—i.e., the maximum displacement or movement of a point on the wave; and, as the wave passes through a substance, its amplitude steadily decreases.

Explanation:

3 0
3 years ago
4 The time to failure of an electrical component has a Weibull distribution with parameters λ = 0.056 and a = 2.5. A random coll
vivado [14]

Answer:

the probability that at least 125 of the 500 components will have failure times larger than 20 is 0.7939

Explanation:

see the attached file

5 0
4 years ago
A 22kg box slides down a 30.0 degree incline. If there is no friction, what is the acceleration of the box?
Rashid [163]

Answer:

Acceleration of the box is 4.9 m/s².

Explanation:

The free body diagram is shown below.

The weight of the body can be resolved into two mutually perpendicular components as shown. The force responsible for sliding motion of the box along the incline is due to mg\sin \theta acting along the incline.

Therefore, as per Newton's second law of motion,

Net force = mass\times acceleration

Now, net force acting along the incline is only mg\sin \theta

Therefore,

mg\sin \theta=ma\\a=g\sin \theta

Now, g=9.8\textrm{ and } \theta = 30

Therefore, the acceleration of the box is given as:

a=9.8\times \sin(30)=9.8\times 0.5=4.9\textrm{ }m/s^{2}

Acceleration of the box is 4.9 m/s².

6 0
4 years ago
A 0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. What force was necessary fo
frutty [35]

Answer:

90 N

Explanation:

The force applied to the ball is given by:

F=\frac{\Delta p}{\Delta t}

where

\Delta p is the change in momentum of the ball

\Delta t is the time taken

The change on momentum of the ball is:

\Delta p=m\Delta v=(0.45 kg)(20 m/s)=9 kg m/s

So, the force applied is

F=\frac{9 kg m/s}{0.10 s}=90 N

6 0
3 years ago
Read 2 more answers
A 100.0-kg bakery sign hangs from two thin cables as shown.
harina [27]

Answer:

1. T₁ = 500 N

2. T₂ = 866 N

Explanation:

Please see attached photo for the diagram.

Thus, we can obtain obtained the value of T₁ and T₂ as follow:

1. Determination of T₁

Angle θ = 30

Hypothenus = 100 kg

Opposite = T₁ =?

Sine θ = Opposite /Hypothenus

Sine 30 = T₁ / 100

Cross multiply

T₁ = 100 × Sine 30

T₁ = 100 × 0.5

T₁ = 50 Kg

Multiply by 10 to express in Newton

T₁ = 50 × 10

T₁ = 500 N

2. Determination of T₂

Angle θ = 60

Hypothenus = 100 kg

Opposite = T₂ = ?

Sine θ = Opposite /Hypothenus

Sine 60 = T₂ / 100

Cross multiply

T₂ = 100 × Sine 60

T₂ = 100 × 0.8660

T₂ = 86.6 Kg

Multiply by 10 to express in Newton

T₂ = 86.6 × 10

T₂ = 866 N

5 0
3 years ago
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