Answer:
If the ship speed is doubled, then the power developed is 8 times the initial value.
Explanation:
ship power is roughly proportional to the cube of the speed, so
P ∝ v³
If the speed is doubled, then the power developed becomes
P ∝ (2)³ = 8 times
Therefore, if the ship speed is doubled, then the power developed is 8 times the initial value.
Answer:
If a negatively charged balloon is brought near one end of the rod but not in direct contact, then <u>the negative charges on the balloon repel the same amount of negative charges on the end of the rod that is close to the balloon</u>, and the positive charges stay at the balloon-side of the rod. The total charge of the rod is still zero, but the distribution of the charges are now non-uniform.
Because the coefficient of friction depends on the surface
The elastic potential energy stored in the stretched spring is 1 J.
<h3>What is Hooke's law?</h3>
Hooke's law states that; provided the elastic limit is not exceeded, the extension of the spring is directly proportional to the force on the spring.
Given that;
Force on the spring = 350 Newton
Distance stretched = 7 centimeters or 0.07 m
Hence;
F = ke
k = F/e = 350 Newton/0.07 m = 5000 N/m
Work done in stretching a spring = 1/2ke^2
= 0.5 × 5000 × (2 × 10^-2)^2 =1 J
Learn more about elastic potential energy: brainly.com/question/156316
Answer: 1.2m/s^2
Explanation: the force exerted on the car is 900N upwards
The mass of the car is 750kg
According to Newton's third law acceleration is proportional to force
F = ma
900 = 750a
a = 900/750
a = 1.2m/s^2
