Is it possible to apply the same amount of force and do different amounts of work?

What is the potential difference across a 15Ω resistor that has a current of 3.0 A?

sesenic [268]

V = I • R

V = (15 ohms) x (3 A)

V = 45 volts

6 0

3 years ago

Read 2 more answers

A charge -353e is uniformly distributed along a circular arc of radius 5.30 cm, which subtends an angle of 48°. What is the line

vladimir2022 [97]

Answer:

- 1.3 x 10⁻¹⁵ C/m

Explanation:

Q = Total charge on the circular arc = - 353 e = - 353 (1.6 x 10⁻¹⁹) C = - 564.8 x 10⁻¹⁹ C

r = Radius of the arc = 5.30 cm = 0.053 m

θ = Angle subtended by the arc = 48° deg = 48 x 0.0175 rad = 0.84 rad (Since 1 deg = 0.0175 rad)

L = length of the arc

length of the arc is given as

L = r θ

L = (0.053) (0.84)

L = 0.045 m

λ = Linear charge density

Linear charge density is given as

$\lambda =\frac{Q}{L}$

Inserting the values

$\lambda =\frac{-564.8\times 10^{-19}}{0.045}$

λ = - 1.3 x 10⁻¹⁵ C/m

4 0

3 years ago

The space program contributes a great deal to enrich the lives of Floridians and beyond. One way that NASA brings an income to F

Ivan

Answer: Through tourism.

Explanation:

Since NASA space centre is located in Florida where NASA launches spaceflight, this is a huge tourist attraction for viewers in the United States and world entirely.

Florida generates income through people coming to view the launch of the spaceflight as tourism.

The tourists help in many ways like lodging into hotels, buying one or two things, taking transport from one place to another which will eventually help Florida economy.

6 0

3 years ago

The gauge pressure inside an alveolus with a 200 µm radius is 25 mmHg, while the blood pressure outside is only 10 mmHg. Assumin

alekssr [168]

Answer:

The surface tension is 0.0318 N/m and is sufficiently less than the surface tension of the water.

Solution:

As per the question:

Radius of an alveolus, R = $200\mu m = 200\times 10^{- 6}\ m$

Gauge Pressure inside, $P_{in} = 25\ mmHg$

Blood Pressure outside, $P_{o} = 10\ mmHg$

Now,

Change in pressure, $\Delta P = 25 - 10 = 15\ mmHg = 1.99\times 10^{3}\ Pa$

Since the alveolus is considered to be a spherical shell

The surface tension can be calculated as:

$\Delta P = \frac{4\pi T}{R}$

$T = \frac{1.99\times 10^{3}\times 200\times 10^{- 6}}{4\pi} = 0.0318\ N/m = 0.318\ mN/m$

And we know that the surface tension of water is 72.8 mN/m

Thus the surface tension of the alveolus is much lesser as compared to the surface tension of water.

3 0

3 years ago

A resistor of 5 Ω is placed in a circuit. The voltage drop across the resistor is 12 V. What is the current through the resistor

Kaylis [27]

Data:

R = 5 Ω
U = 12 V
i = ?

Formula:

 $U = R*i$ → $i = \frac{U}{R}$ 

Solving:

 $i = \frac{U}{R}$
$i = \frac{12}{5}$
$\boxed{i = 2.4A}$

Answer:

The current through the resistor is 2.4 Amperes

5 0

3 years ago