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3 years ago

15

A sample of grape juice has a hydroxide ion concentration of 1.4 × 10-10 M

2 answers:

MArishka [77]3 years ago

5 0

The relation between hydroxide ion (OH-) and hydronium ion (H3O+) is given by:

pH + pOH = 14, which is equivalent to [H3O+] [OH-] = 10^ -14

=> [H3O+] = (10^ -14) / [OH-] = (10^ -14) / (1.4*10^-10) = 0.71 * 10^ - 4 = 0.071 * 10^-5

Answer: 0.071 * 10 ^ -5

finlep [7]3 years ago

4 0

Answer:

7.1 * 10x6^-5M

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4 years ago

When 15.3 g of sodium nitrate, NaNO3,was dissolved in water in a calorimeter, the temperature fell from 25.00oC to 21.56oC. If t

satela [25.4K]

Answer:

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

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Heat lost by solution ad calorimeter = Q

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Heat gained by sodium nitrate = -Q = -(-3,684.24 J)=3,684.24 J

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