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3 years ago

What is the dependent variable in an experiment that shows how the volume of a gas changes with change in temperature?

Physics

1 answer:

Natali5045456 [20]3 years ago

6 0

Answer:

Volume of gas

Explanation:

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If the magnitude of the magnetic force on a proton is F when it is moving at 14.0 o with respect to the field, what is the magni

sergeinik [125]

Answer:

The magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F

Explanation:

Given;

magnitude of the magnetic force is F at 14.0⁰ with respect to the field.

To determine the magnitude of the magnetic force at 32.5⁰ to the field, we apply the following formula and solve with proportion;

f*Sin(14.0⁰) = F

f*Sin(32.5⁰) = ?

$= \frac{f*Sin(32.5^o)}{f*Sin(14.0^o)}.F\\\\ =2.22 \ F$

Therefore, the magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F

6 0

4 years ago

4. Two people each have a mass of 55 kg. They are both in an

mestny [16]

Answer:

350 N

Explanation:

F=ma

$f = force \\ m = mass \\ a = acceleration$

$m = 2(55kg) + 240kg \\ a = 1.0 \frac{m}{ {s}^{2} }$

Force = 350 Newtons

4 0

3 years ago

Tarzan swings back and forth on a

WARRIOR [948]

Answer:

Considering Tarzan as a point mass at point L and using the equation for a simple pendulum:

P = 2 pi (L / g)1/2

P^2 = 4 pi^2 L / g

L = g P^2 / (4 pi^2) = 9.8 m/s^2 * 7.27^2 s^2 / (4 pi^2) = 13.1 m

4 0

3 years ago

The 5-lb collar is released from rest at A and travels along the frictionless guide. Determine the speed of the collar when it s

Sholpan [36]

Answer:

Explanation:

Stiffness of spring k equal to 4 lb/ft.

Unstretched length of the spring L is equal to 0.5 feet.

Weight of the collar W is 15lb

Radius of curvature of curve guide is 1 feet

length of vertical rod is 1.5 feet

Initial speed of collar when released from rest at A is 0 feet per seconds

use the energy conservation equation

$P_A +K_A=P_B+K_B$

Estimate the potential energy , component as position B as below

$P_A=Wh_1+\frac{1}{2} ks^2_1\\\\=5\times(1.5+1)+\frac{1}{2} \times 4 \times(1.5+1-0.5)^2\\\\=20.5lb.ft$

Estimate the kinetic energy , component as position A as below

$K_A=\frac{1}{2} \frac{W}{g} V^2_1\\\\=\frac{1}{2} \frac{5}{32.2} \times0^2\\\\=0lb.ft$

Estimate the kinetic energy , component as position B as below

$K_A=\frac{1}{2} \frac{W}{g} V^2_2\\\\=\frac{1}{2} \frac{5}{32.2} \times V^2_2\\\\=00777V^2_2$

Substitute 20.5lb- ft for $P_A$

0.5lb-ft for $P_B$

0lb -ft for $K_A$

$0.0777V_2^2 for K_B$

$20.5+0=0.5+0.777V^2_2\\\\V^2_2=257.6\\\\V_2=16.05$

= 16.05ft/sec

7 0

3 years ago

When you have been swimming swimming and you come out of the pool, you may feel cold. Use your understanding of endothermic proc

Leona [35]

Explanation:

Edothermic process is the absorbtion of heat.

It is the opposite of exothermic process which is the release of energy. In edothermic process thermal energy is absorbed from the surrounding

4 0

3 years ago