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irakobra [83]
3 years ago
12

{8}+\cfrac{3}{8}" alt="\bf \cfrac{5}{8}+\cfrac{3}{8}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
weeeeeb [17]3 years ago
8 0

Answer:

The answer is 1

Step-by-step explanation:

mojhsa [17]3 years ago
3 0

Answer:

1

Step-by-step explanation:

I hope it's helpful for you

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Can you please help with this question
dexar [7]
The surface area of a cube is simply the area of one face multiplied by 6, since all of the 6 faces are exactly the same, therefor:
Surface area = 5*5*6 = 150 ft^2
5 0
3 years ago
At a football game, 65% of people attending were supporting the home team, while 35% were supporting the visiting team. If 1300
Misha Larkins [42]

Answer: 2000

Step-by-step explanation:

At a football game, 65% of people that will attend are supporting the home team, while 35% are supporting the visiting team. 1300 people that attended supported the home team.

To get the total number of people that attended the game, we have to find the number of away supporters as well.

Let the number of people that attended the game be y.

Therefore 65% of y = 1300

65/100 × y = 1300

0.65 × y = 1300

0.65y = 1300

Divide both side by 0.65

0.65y/0.65 = 1300/0.65

y = 2000

The total number of people attending the game is 2000.

8 0
3 years ago
4) (Assume AR is tangent)<br>Given: AR 12<br>SR - 7.7<br>Find: cs (Round to nearest tenth.)​
andreev551 [17]

The length of CS is 11.0

Explanation:

Given that the length of the tangent AR is 12

The length of SR is 7.7

To find: The length of CS

The<u> tangent secant theorem</u> states that "if a tangent and a secant are drawn from an external point to a circle, then the square of the measure of the tangent is equal to the product of the measures of the secant’s external part and the entire secant."

Applying the tangent secant theorem, we have,

AR^2=SR\times RC

Rewriting the above equation, we get,

AR^2=SR(SR+SC)

Substituting the values, we get,

12^2=7.7(7.7+CS)

Simplifying, we have,

144=59.29+7.7CS

Subtracting both sides by 59.29, we get,

84.71=7.7CS

Dividing both sides by 7.7, we have,

11.0013=CS

Rounding off to the nearest tenth, we get,

11.0=CS

Thus, the length of CS is 11.0

6 0
3 years ago
Here is the question here please answer
earnstyle [38]

Daaaaaaaaaammmmm that’s hard

4 0
3 years ago
Every prime number greater than 10 has a digit in the ones place that is include in wich set of numbers A- 1,3,7,9 B-1,3,5,9 D-1
marta [7]

That's very interesting.  I had never thought about it before.
Let's look through all of the ten possible digits in that place,
and see what we can tell:

-- 0:
   A number greater than 10 with a 0 in the units place is a multiple of
   either 5 or 10, so it's not a prime number.

-- 1:
    A number greater than 10 with a 1 in the units place could be
    a prime (11, 31 etc.) but it doesn't have to be (21, 51).

-- 2:
   A number greater than 10 with a 2 in the units place has 2 as a factor
   (it's an even number), so it's not a prime number.

-- 3:
   A number greater than 10 with a 3 in the units place could be
   a prime (13, 23 etc.) but it doesn't have to be (33, 63) .

-- 4: 
   A number greater than 10 with a 4 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 5:
   A number greater than 10 with a 5 in the units place is a multiple
   of either 5 or 10, so it's not a prime number.

-- 6:
   A number greater than 10 with a 6 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 7:
   A number greater than 10 with a 7 in the units place could be
   a prime (17, 37 etc.) but it doesn't have to be (27, 57) .

-- 8:
   A number greater than 10 with a 8 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 9:
   A number greater than 10 with a 9 in the units place could be
   a prime (19, 29 etc.) but it doesn't have to be (39, 69) .

So a number greater than 10 that IS a prime number COULD have
any of the digits  1,  3,  7,  or  9  in its units place.

It CAN't have a  0,  2,  4,  5,  6,  or  8 .

The only choice that includes all of the possibilities is  'A' .

4 0
3 years ago
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