<img src="https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B5%7D%7B8%7D%2B%5Ccfrac%7B3%7D%7B8%7D" id="TexFormula1" title="\bf \cfrac{5}

irakobra [83]

3 years ago

{8}+\cfrac{3}{8}" alt="\bf \cfrac{5}{8}+\cfrac{3}{8}" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

weeeeeb [17]3 years ago

8 0

Answer:

The answer is 1

Step-by-step explanation:

mojhsa [17]3 years ago

3 0

Answer:

Step-by-step explanation:

I hope it's helpful for you

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A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.

yawa3891 [41]

Answer:

The probability is 0.003

Step-by-step explanation:

We know that the average $\mu$ is:

$\mu=500$

The standard deviation $\sigma$ is:

$\sigma=100$

The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

We seek to find

$P(x800)$

For P(x>800) The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

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$Z=3$

The score of Z = 3 means that 800 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

$P(x>800)=0.15\%$

For P(x<200) The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

$Z=\frac{200-500}{100}$

$Z=-3$

The score of Z = -3 means that 200 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

$P(x$