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Len [333]
3 years ago
13

Given: Circumscribed ABCD, AB=5,AD=8, CD=10. Find: BC

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0

Answer:

BC=7

Step-by-step explanation:

The circle can be circumscribed into the quadrilateral, if the sums of the opposite sides of the quadrilateral are eqaul.

Thus,

AB+CD=AD+BC,\\ \\8+BC=5+10,\\ \\BC=15-8=7.

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Answer:

Step-by-step explanation:

Call T the top

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T G B is a right triangle

37 at B, 90 at G, thus 53 at BTG

TGA is a right triangle

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thus 122 at ABT

law of sines:

sin 25 / BT = sin 12/ 57

so BT = 156 meters (first answer)

now angle ABT = 180 - 12 - 25

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so

sin 143 /AT = sin12/57

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4 0
2 years ago
Please some help for question 1
o-na [289]

Answer:

f (3) is equal to 31

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7 0
2 years ago
Read 2 more answers
Suppose it is known that for a given differentiable function y=f(x), its tangent line (local linearization) at the point where a
AleksandrR [38]

Answer:

y(-4) = 5

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Step-by-step explanation:

Hi!

Since the tangent line T and the curve y must coincide at x=-4

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On the other hand, the derivative of the curve evaluated at -4 y'(x=-4) must be the slope of the tangent line. Which inspecting the tangent line T(x) is -7

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y'(-4) = -7

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