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krok68 [10]
3 years ago
15

A 4.0 kg object will have a weight of approximately 14.8 N on Mars. What is the gravitational field strength on Mars?

Physics
2 answers:
zhannawk [14.2K]3 years ago
8 0
Field strength =force/unit mass
= 14.8N/ 4kg = 3.7N/kg
Shalnov [3]3 years ago
8 0

Answer:

The gravitational field strength on Mars is 3.7 N/kg.

Explanation:

Given that,

Mass of the object, m = 4 kg

Weight of the object on Mars, F = W = 14.8 N

We need to find the gravitational field strength on Mars. It is given by gravitational force per unit mass of an object. Mathematically, it is given by

G=\dfrac{F}{m}

G=\dfrac{14.8\ N}{4\ kg}

G = 3.7 N/kg

So, the gravitational field strength on Mars is 3.7 N/kg. Hence, this is the required solution.

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6 0
2 years ago
In a certain process, the energy of the system decreases by 250 kJ. The process involves 480 kJ of work done on the system. Find
gregori [183]

Answer:

Q = - 730 KJ

730 KJ is transferred out of the system

Explanation:

According to the first law of thermodynamics, energy can neither be created nor destroyed, but can be transformed from one form to another.

For a particular process/system, the first law is interpreted as

ΔU = Q + W (depending on convention, some textbooks give this relation as ΔU = Q - W)

ΔU is the change in internal energy of the system, in my convention, it is positive if the internal energy increases and negative otherwise.

Q = Heat transferred into or out of the system. Q is positive for heat transferred into the system and negative for heat transferred out of the system.

W = workdone by the system or work done on the system. W is positive for workdone on the system and W is negative for when work is done by the system.

ΔU decreases by 250 KJ, that is, ΔU = - 250 KJ

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- 250 = Q + 480

Q = - 250 - 480 = - 730 KJ

The heat is transferred out of the system.

6 0
2 years ago
Read 2 more answers
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