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alina1380 [7]
2 years ago
9

A cubical gaussian surface surrounds a long, straight, charged filament that passes perpendicularly through two opposite faces.

No other charges are nearby. (ii) Through how many of the cube's faces is the electric flux zero? Choose from the same possibilities as in part (i).
Physics
1 answer:
laiz [17]2 years ago
7 0

Answer:

The electric flux is zero through four cube surfaces given that a cubical gaussian surface surrounds a long, straight, charged filament that passes perpendicularly through two opposite faces.

Explanation:

Assuming the charged filament is quite long and you are not near the edges, the two opposing sides that the filament travels through have no flux. If the charge filament is long, which you may assume is indefinitely long, then there is the equal amount of charge on the left and right of where you are, therefore the electric field has no preference for left or right. This implies that the electric field can only travel in or out of the filament. No field lines run through the two faces of the cube that the filament goes through if the electric field is not moving left or right. There are electric field lines on the four sides of the filament.

To learn more about cubical gaussian surface and electric flux. Click brainly.com/question/13003911

#SPJ4

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Answer:here you goo

Explanation:

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2 years ago
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1. A step-up transformer increases 15.7V to 110V. What is the current in the secondary as compared to the primary? Assume 100 pe
Serjik [45]

1. I_2 = 0.14 I_1

Explanation:

We have:

V_1 = 15.7 V voltage in the primary coil

V_2 = 110 V voltage in the secondary coil

The efficiency of the transformer is 100%: this means that the power in the primary coil and in the secondary coil are equal

P_1 = P_2\\V_1 I_1 = V_2 I_2

where I1 and I2 are the currents in the two coils. Re-arranging the equation, we find

\frac{I_2}{I_1}=\frac{V_1}{V_2}=\frac{15.7 V}{110 V}=0.14

which means that the current in the secondary coil is 14% of the value of the current in the primary coil.

2. 5.7 V

We can solve the problem by using the transformer equation:

\frac{N_p}{N_s}=\frac{V_p}{V_s}

where:

Np = 400 is the number of turns in the primary coil

Ns = 19 is the number of turns in the secondary coil

Vp = 120 V is the voltage in the primary coil

Vs = ? is the voltage in the secondary coil

Re-arranging the formula and substituting the numbers, we find:

V_s = V_p \frac{N_s}{N_p}=(120 V)\frac{19}{400}=5.7 V

5 0
3 years ago
Three boards, each 50 mm thick, are nailed together to form a beam that is subjected to a 1200-N vertical shear. Knowing that th
lisabon 2012 [21]

Answer:

Using equation

qs=F

q=VQ/I   V=1200

q=998.45 N

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s=F/q

s=700/998.45

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3 years ago
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A classmate is attempting to draw a free body diagram for a box being pushed across the floor at a constant speed. The image bel
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Answer:

A. The applied force should be the same size as the friction force

Explanation:

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<u>A. The applied force should be the same size as the friction force</u>

7 0
3 years ago
A pin fin of uniform, cross-sectional area is fabricated of an aluminum alloy (k = 160 W/m-K). The fin diameter is D = 4 mm, and
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Answer:

Given that

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By solving above equation we get

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