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alina1380 [7]
2 years ago
9

A cubical gaussian surface surrounds a long, straight, charged filament that passes perpendicularly through two opposite faces.

No other charges are nearby. (ii) Through how many of the cube's faces is the electric flux zero? Choose from the same possibilities as in part (i).
Physics
1 answer:
laiz [17]2 years ago
7 0

Answer:

The electric flux is zero through four cube surfaces given that a cubical gaussian surface surrounds a long, straight, charged filament that passes perpendicularly through two opposite faces.

Explanation:

Assuming the charged filament is quite long and you are not near the edges, the two opposing sides that the filament travels through have no flux. If the charge filament is long, which you may assume is indefinitely long, then there is the equal amount of charge on the left and right of where you are, therefore the electric field has no preference for left or right. This implies that the electric field can only travel in or out of the filament. No field lines run through the two faces of the cube that the filament goes through if the electric field is not moving left or right. There are electric field lines on the four sides of the filament.

To learn more about cubical gaussian surface and electric flux. Click brainly.com/question/13003911

#SPJ4

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A 7.0 mm -diameter copper ball is charged to 40 nC. What fraction of its electrons have been removed? The density of copper is 8
mylen [45]

Answer:

f = 2.6 \times 10^{-13}

Explanation:

Let the mass of copper ball is "m" gram

now the total number of copper atom present in the ball is given as

N = \frac{m}{29} \times 6.02 \times 10^{23}

now the total number of electrons in one copper atom is 29

so total number of electrons in given sample of copper ball is

N_e = m(6.02 \times 10^{29})

now diameter of the ball is 7.0 mm

density of the ball = 8900 kg/m^3

now we have

m = (\frac{4}{3}\pi r^3)(8900)

m = (\frac{4}{3}\pi(\frac{0.007}{2})^3)(8900)

m = 1.6 gram

now we have

N_e = 9.63 \times 10^{23}

now the charge on the copper ball is 40 nC

so the number of electrons removed

Q = ne

40 \times 10^{-9} = n(1.6 \times 10^{-19}

n = 2.5 \times 10^{11}

so the fraction of number of electrons removed is given as

f = \frac{n}{N_e}

f = \frac{2.5 \times 10^{11}}{9.63 \times 10^{23}}

f = 2.6 \times 10^{-13}

7 0
4 years ago
Which of the following does not serve as a way to neutralize the charge in a body?
Brrunno [24]

Answer:

B. Adding more protons to a positively charged body until the number of protons matches the number of electrons

Explanation:

5 0
4 years ago
5. Which describes the reaction of a substance to form one or more nen substances?
murzikaleks [220]

Answer:

A chemical reaction

Explanation:

In a physical change the chemical composition of a matter stays the same. One example is a change in state of matter. Consider water, you can heat it to vapour and cool it to form ice but you can get the exact same mass and colour after any physical change happens.

To form a two or more substance an internal arrangement of atoms must happen. For that chemical change should occur as only in chemical reactions atoms are rearrange to form new substances.

5 0
4 years ago
The process of blood cell formation is called
Andreyy89
Hemapoteisis



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7 0
3 years ago
A machine gun fires 60 bullets per minute, with a velocity of 700 m/s .If each bullet has a mass of 50 g .Find the power develop
MAXImum [283]

Answer:

2100 kg*m/s

Explanation:

The proper term for power in this case is to use the physics term "impuls" = p.

1. Find the "power" developed by the gun to fire just 1 bullet.

2. multiply by 60 to find the power produced by the gun per minute.

p = m * v

where

m = mass of the bullet = 50 g = 0.050 kg

v = velocity of the bullet = 700 m/s

p = 0.050 * 700

p = 35 kg*m/s

So the impuls for 1 bullet is 35 kg*m/s

The gun can fire 60 bullets per minute so it's fireing power must there fore be 60 * 35 = 2100 kg*m/s

4 0
3 years ago
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