If the light from the sun has higher frequencies from one side of the sun than from the other side, it is proof that the Sun is rotating.
Doppler effect states that, if a person is standing still and a source ( sound / light ) is moving towards him, the frequency of the wave emitted from the object will increase and if the source ( sound / light ) is away from him, the frequency of the wave emitted from the object will decrease.
So, if the light from the sun has higher frequencies from one side of the sun than from the other side, it means that the Sun is rotating. The higher frequencies points are the points that rotating towards Earth and lower frequencies points are the points that rotating away from Earth.
Therefore, if the light from the sun has higher frequencies from one side of the sun than from the other side, it is proof that the Sun is rotating.
To know more about Doppler Effect
brainly.com/question/15318474
#SPJ1
Answer: True
Explanation: Because of the way this water cycle has always circulated our planet, there is indeed a chance that the water in your glass is the same water that thirsty dinosaurs were drinking about 65 million years ago
Answer:
In an inductive circuit, when frequency increases, the circuit current decreases and vice versa.
Explanation:
Answer:
f1 = 58.3Hz, f2 = 175Hz, f3 = 291.6Hz
Explanation:
lets assume speed of sound is 350 m/s.
frequencies of a standing wave modes of an open-close tube of length L
fm = m(v/4L)
where m is 1,3,5,7......
and fm = mf1
where f1 = fundamental frequency
so therefore: f1 = 350 x 4 / 1.5
f1 = 58.3Hz
f2 = 3 x 58.3
f2 = 175Hz
f3 = 5 x 58.3
f3 = 291.6Hz
So, the speed of the ball after 2 seconds after free fall is <u>20 m/s</u>.
<h3>Introduction</h3>
Hi ! I'm Deva from Brainly Indonesia. In this material, we can call this event "Free Fall Motion". There are two conditions for free fall motion, namely falling (from top to bottom) and free (without initial velocity). Because the question only asks for the final velocity of the ball, in fact, we may use the formula for the relationship between acceleration and change in velocity and time. In general, this relationship can be expressed in the following equation :
![\boxed{\sf{\bold{a = \frac{v_2 - v_1}{t}}}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%7B%5Cbold%7Ba%20%3D%20%5Cfrac%7Bv_2%20-%20v_1%7D%7Bt%7D%7D%7D%7D%20)
With the following conditions :
- a = acceleration (m/s²)
= speed after some time (m/s)
= initial speed (m/s)- t = interval of time (s)
<h3>Problem Solving</h3>
We know that :
- a = acceleration = 9,8 m/s² >> because the acceleration of a falling object is following the acceleration of gravity (g).
= initial speed = 0 m/s >> the keyword is free fall- t = interval of time = 2 s
What was asked :
= speed after some time = ... m/s
Step by step :
![\sf{a = \frac{v_2 - v_1}{t}}](https://tex.z-dn.net/?f=%20%5Csf%7Ba%20%3D%20%5Cfrac%7Bv_2%20-%20v_1%7D%7Bt%7D%7D%20)
![\sf{(a \times t) + v_1 = v_2}](https://tex.z-dn.net/?f=%20%5Csf%7B%28a%20%5Ctimes%20t%29%20%2B%20v_1%20%3D%20v_2%7D%20)
![\sf{(10 \times 2) + 0 = v_2}](https://tex.z-dn.net/?f=%20%5Csf%7B%2810%20%5Ctimes%202%29%20%2B%200%20%3D%20v_2%7D%20)
![\boxed{\sf{v_2 = 20 \: m/s}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%7Bv_2%20%3D%2020%20%5C%3A%20m%2Fs%7D%7D%20)
So, the speed of the ball after 2 seconds after free fall is 20 m/s.