since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

$\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1$

So probabaility for $\mathrm{X}=1$ is

$P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679$

So expected frequency for $X=1$ is $0.3679^{*} 30=11.037$ (or $\left.11.04\right)$ .

8 0

3 years ago

Two wrongs and One right: vertical angles. Please help only 2-3 questions

luda_lava [24]

Answer:

Solution one is correct and solution 2 and 3 are incorrect

Step-by-step explanation:

You simply make an equation because for vertical angles 2 angles that are across from each other have the same value (in this case 2x+30 and 5x-36.)

The equation: 2x+30=5x-36---->3x=66----> x=22

Solution 1 is correct.

Hope this helped!

3 0

3 years ago

Read 2 more answers