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PolarNik [594]
2 years ago
6

The equation for the vertical line that goes through point V (−5, 17).

Mathematics
1 answer:
valentinak56 [21]2 years ago
4 0

Answer:

The answer to the above question is x = -5

You might be interested in
Solve this equation by using the look inside method to rewrite the problem <br><br> -81 = 3(5 - 4r)
TEA [102]
-81=3(5-4r)
27=-(5-4r)
27=-5+4r
-4r=-5-27
-4r=-32
r=8

Hope my answer helped u :)
4 0
3 years ago
Can someone help me with this
VikaD [51]

Answer:

A. y = 3x.

Step-by-step explanation:Relation 2 is a straight line that does not pass through the origin, so it is a partial variation.

6 0
2 years ago
What is f(0) if f(t) = t^2 – 2t – 2?
Dafna11 [192]

Answer:

-2

Step-by-step explanation:

f(t) = t^2 – 2t – 2

To find f(0), replace t with 0 in the expression and evaluate the expression.

f(0) = 0^2 – 2(0) – 2

f(0) = -2

6 0
3 years ago
Read 2 more answers
In the expression (x^2 + 3), the base is ?
azamat
Answer to your question
The base is X
What are the other stuff then?
2 is the power
3 is the constant

8 0
2 years ago
Please help me find the slope of the line graphed below!
valentinak56 [21]

Answer:

slope = - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 1, 0) and (x₂, y₂ ) = (0, - 3) ← 2 points on the line

m = \frac{-3-0}{0+1} = \frac{-3}{1} = - 3

8 0
3 years ago
Read 2 more answers
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