Answer:
i think the answer is yess
Answer:
pH = 10.38
Explanation:
∴ molar mass C9H13N = 135.21 g/mol
∴ pKb = - log Kb = 4.2
⇒ Kb = 6.309 E-5 = [OH-][C9H20O3N+] / [C9H13N]
∴ <em>C</em> sln = (205 mg/L )*(g/1000 mg)*(mol/135.21 g) = 1.516 E-3 M
mass balance:
⇒ <em>C</em> sln = 1.516 E-3 = [C9H20O3N+] + [C9H13N]......(1)
charge balance:
⇒ [C9H20O3N+] + [H3O+] = [OH-]; [H3O+] is neglected, come from water
⇒ [C9H20O3N+] = [OH-].......(2)
(2) in (1):
⇒ [C9H13N] = 1.516 E-3 - [OH-]
replacing in Kb:
⇒ Kb = 6.3096 E-5 = [OH-]² / (1.516 E-3 - [OH-])
⇒ [OH-]² + 6.3096 E-5[OH] - 7.26613 E-8 = 0
⇒ [OH-] = 2.3985 E-4 M
∴ pOH = - Log [OH-]
⇒ pOH = 3.62
⇒ pH = 14 - pOH = 14 - 3.62 = 10.38
Explanation:
Since, the given reaction is as follows.
Hence, rate law of the reaction is as follows.
R = ![k[NO][Cl_{2}]](https://tex.z-dn.net/?f=k%5BNO%5D%5BCl_%7B2%7D%5D)
As it is known that rate of a reaction depends on the initial concentration of products. So here, the rate of reaction will depend on the concentration of NO and 
. Since, power of the concentrations of each of these is equal to 1. Therefore, order of the reaction is equal to 1 + 1 = 2.
According to the rate law, reactants involved in the rate determining step are NO and . Hence, first step of the mechanism is the rate determining step.
Also, according to the rate of reaction doubling the concentration of NO will double the rate of reaction.
The number of reactants taking part in a single step of the reaction is known as molecularity of the reaction. Therefore, molecularity of the first step of the reaction is 2.
Both the given steps are not termolecular.
I believe a possible Lewis dot structure that does not obey the octet rule, where all elements are required to have 8 electrons in their outermost shell, would be the SF4 molecule.
Sulfur can contain an more than 8 electrons, in this molecule and thus has an expanded octet.
Answer:
This question is incomplete
The completed question is below
Which pair of molecules is expected to have the most different properties?
CO and NO
SO₂ and CH₄
The correct answer is SO₂ and CH₄
Explanation:
All the four substances are gases at room temperature.
Carbon monoxide (CO) and nitric oxide (NO) are both reactive oxides. They are both polar and inorganic also, hence should have some similar properties (based on there origin/composition and polarity).
Sulphur dioxide (SO₂) is polar because it's a bent molecule, methane (CH₄) is non-polar because of the tetrahedral shape of it's molecule. Methane is an organic molecule while sulphur dioxide is an inorganic molecule.
From the above, <u>it can be deduced that SO₂ and CH₄ are expected to have different properties</u>. For example, the polarity of SO₂ makes it dissolve in water to form an acidic solution while methane does not dissolve in water and hence doesn't form an acidic solution.
