Fluid of intelligent

1 answer:

8 0

"Fluid intelligence involves being able to think and reason abstractly and solve problems. This ability is considered independent of learning, experience, and education. Examples of the use of fluid intelligence include solving puzzles and coming up with problem-solving strategies."

- Verywell Mind

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An incline plane has Ф = 40.0° and μ k = 0.15. Starting from rest, how long will it take a 4.0 kg block to reach a speed of 12 m

lesya [120]

The block on the action of two forces, the Force of Friction and the Tangential Weight. Using the Newton's Secound Law, we have:

$P_{t}-Fat=ma \\ mgsen\O-mgucos\O=ma \\ a=g(sen\O-ucos\O)$

Using the Velocity Hourly Equation, we get:

$V=V_{o}+a\Delta t \\ \Delta t= \frac{V}{a}$

Uniting the equations:

$\Delta t= \frac{V}{g(sen\O-ucos\O)}$

Entering the unknowns:

$\Delta t= \frac{V}{g(sen\O-ucos\O)} \\ \Delta t= \frac{12}{10(sen40^o-0.15cos^o)} \\ \Delta t= \frac{12}{10(0,64-0.15x0.77)} \\ \Delta t= \frac{12}{5.27} \\ \boxed {\Delta t=2.28s}$

Obs: Approximate results

If you notice any mistake in my english, please let me know, because i am not native.

5 0

3 years ago

A 12 volt battery in a motor vehicle is capable of supplying the starter motor with 150 A. It is noticed that the terminal volta

qwelly [4]

Answer: $0.0133 \Omega$

Explanation:

Given

Voltage=12 V

Current(I)=150 A

$V_{terminal}=10 V$

$r_{internal}=\frac{\Delta V}{I}$

$r_{internal}=\frac{12-10}{150}$

$r_{internal}=\frac{2}{150}=0.0133 \Omega$

4 0

3 years ago

What is the approximate weight of a 20-kg cannonball on Earth? 2 N 20 N 196 N 1,960 N

Margaret [11]

Since weight is the force an object is exerting on another object, and the formula to calculate force is Force = Mass * Acceleration, the answer to your question is 196 N, since the mass of the cannonball times Earth's gravitational pull equals 196 N.

5 0

4 years ago

Read 2 more answers

The magnitude J of the current density in a certain wire with a circular cross section of radius R = 2.11 mm is given by J = (3.

oksano4ka [1.4K]

Answer:

$i = 2.84 \times 10^{-3} A$