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Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first bl

o-na [289]

Answer:

The tension in the string connecting block 50 to block 51 is 50 N.

Explanation:

Given that,

Number of block = 100

Force = 100 N

let m be the mass of each block.

We need to calculate the net force acting on the 100th block

Using second law of newton

$F=ma$

$100=100m\times a$

$ma=1\ N$

We need to calculate the tension in the string between blocks 99 and 100

Using formula of force

$F_{100-99}=ma$

$F_{100-99}=1$

We need to calculate the total number of masses attached to the string

Using formula for mass

$m'=(100-50)m$

$m'=50m$

We need to calculate the tension in the string connecting block 50 to block 51

Using formula of tension

$F_{50}=m'a$

Put the value into the formula

$F_{50}=50m\times a$

$F_{50}=50\times1$

$F_{50}=50\ N$

Hence, The tension in the string connecting block 50 to block 51 is 50 N.

8 0

3 years ago

A car is travelling with a velocity of 10 m/s and has a mass of 550 kg. The car has energy.

Elenna [48]

Answer: The car has a kinetic energy (because it's in motion) of: $27500J$

Explanation:

$Formula: E=\frac{1}{2}mv^2$

$E=\frac{1}{2}mv^2$

$E=\frac{1}{2}(550kg)(10m/s)^2$

$E=\frac{1}{2}(550kg)(100m^2/s^2)$

$E=\frac{1}{2}(55000J)\\E=27500J$

3 0

3 years ago

Find the angle of prism if the ray just fail to emerge from 2nd face When ray of light falls normallly on the face of prism of R

Usimov [2.4K]

The angle of prism is 41.81 degrees.

Explanation:

For no emergence to be taken place, inside a prism, Total Internal Reflection (TIR) should take place at the second surface. For TIR, at second surface, angle of refraction must be greater than critical angle. Angle of prism is related to refraction as,

$A>r_{1}+C$

Since, $r_{1}$ = C and $A \geq 2 C$

This implies $A \geq C$

$\sin A \geq \sin C$

$\sin A \geq \frac{1}{\mu}$

$\sin A \geq \frac{2}{3}$

when sin goes to other side become as sin inverse of value, and obtain the result as below,

$A=41.81^{\circ}$

3 0

3 years ago

The separation in time between the arrival of primary and secondary waves is

Gre4nikov [31]

The separation in time between the arrival of primary and secondary wave is called LAG TIME.
The time difference between the arrival of primary wave and secondary wave in a seismogram is called lag time. The primary wave always travels faster than the secondary wave, thus the difference between the two can be obtained by estimating the difference between the arrival time of the two waves/.

3 0

3 years ago

What are groups 1,2 and 3 examples of on the periodic table

pishuonlain [190]

The number of the group identifies the column of the standard periodic table in which the element appears.
Group 1 contains the alkali metals ( lithium (Li), sodium (Na), potassium (K), rubidium (Rb), caesium (Cs), and francium(Fr).)
Group 2 contains the alkaline earth metals ( beryllium (Be),magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba) and radium (Ra) )
Group 3: Scandium (Sc) and yttrium (Y)

4 0

3 years ago