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IceJOKER [234]
3 years ago
11

A cargo elevator on Earth (where g = 10 m/s2) lifts 3000 kg upwards by 20 m. 720 kJ of electrical energy is used up in the proce

ss. What is the efficiency of this process?
Physics
1 answer:
MakcuM [25]3 years ago
8 0

Answer: 83%

Explanation:

Efficiency of the process = work output/work input × 100%

Work input is the energy used up in the process = 720,000Joules

Work output = Force × distance

= (3000×10)× 20

= 600000 Joules

Efficiency= 600000/720000 × 100

= 0.83×100

= 83%

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Answer:

q=+8.01\cdot 10^{-19}\ coulombs

Explanation:

<u>Elementary charge</u>

The elementary charge, denoted by the symbol e is the electric charge carried by a proton or, equivalently, the magnitude of a negative electric charge carried by an electron, which has charge −e.

The value of the elementary charge is a fundamental constant in physics:

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If a metal sphere has an excess of +5 elementary charge, then it has a net charge of:

q=5*\mathbf{e}=+5*1.60217662 \cdot 10^{-19}\ coulombs

\boxed{q=+8.01\cdot 10^{-19}\ coulombs}

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