Answer:
<em>radius of the loop = 7.9 mm</em>
<em>number of turns N ≅ 399 turns</em>
Explanation:
length of wire L= 2 m
field strength B = 3 mT = 0.003 T
current I = 12 A
recall that field strength B = μnI
where n is the turn per unit length
vacuum permeability μ = 
= 1.256 x 10^-6 T-m/A
imputing values, we have
0.003 = 1.256 x 10^−6 x n x 12
0.003 = 1.507 x 10^-5 x n
n = 199.07 turns per unit length
for a length of 2 m,
number of loop N = 2 x 199.07 = 398.14 ≅ <em>399 turns</em>
since there are approximately 399 turns formed by the 2 m length of wire, it means that each loop is formed by 2/399 = 0.005 m of the wire.
this length is also equal to the circumference of each loop
the circumference of each loop = 
0.005 = 2 x 3.142 x r
r = 0.005/6.284 = 
= 0.0079 m =<em> 7.9 mm</em>
<span>Air resistance, also called
drag, acts upon a falling body by slowing the body down to the point
where it stops accelerating, and it falls at a constant speed, known as
the terminal velocity of a falling object. Air resistance
depends on the cross-sectional area of the object, which is why the
effect of air resistance on a large flat-surfaced object is much greater
than on a small, stream-lined object.</span>
Answer:
Explanation:
From the question we are told that:
Time 
Angular displacement 
Final Angular velocity 
Let
Angular acceleration 
Generally the equation for Initial Angular velocity 
is mathematically given by
Also,Initial Angular velocity is mathematically given by
Therefore substitution
Substitution in the 2nd equation for Initial Angular velocity
