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Delicious77 [7]
3 years ago
11

Asteroid Toutatis passed near Earth in 2006 at four times the distance to our Moon. This was the closest approach we will have u

ntil 2060. If it has mass of 5.0×1013kg , what force did it exert on Earth at its closest approach?
Physics
1 answer:
marissa [1.9K]3 years ago
7 0

Answer:

The answer is 8.44*10^9 Newton

Explanation:

The equation for universal gravitation is:

F=G*m_{1}*m_{2}/r^{2}

Where:

G= 6.674×10^−11 N · (m/kg)^2

M(earth)=5.972 × 10^24 kg

M(asteroid)=5.0×10^13 kg

r=1.537*10^9 m (Calculated from average distance between moon and earth)

The force will be:

F=6.674*10^{-11}*5.972*10^{24}*5*10^{13}/(1.537*10^9)^2\\F=8.44*10^9

8.44*10^9 Newton

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