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Norma-Jean [14]
2 years ago
5

Fill in the blank! (for 15 pts)

Chemistry
1 answer:
Artist 52 [7]2 years ago
4 0

In order:

alkali

reactive

shiny

electricity

soft

low

good luck!

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AysviL [449]

Answer:

3

Explanation:

4 0
3 years ago
The alkali metals all react with water. which is the most reactive metal?
kifflom [539]
Alkali Metals (Group 1) elements experience an increase in the vigour of their reaction in water as they go down the group (as the atomic number increase). As such the most reactive Alkali Metal would be FRANCIUM, which is at the base of Group One.


Quite frankly, you do not want Francium to react with water- that's a huge explosion on your hand.

8 0
3 years ago
Steven had a sample of ethanol and wanted to see if it would boil at the temperature found in his textbook. His experiment yield
Natasha_Volkova [10]

Answer:

17.04%

Explanation:

Actual Value = 173.1

Measured Value = 143.6

Percent error is obtained using the equation;

Percent error = (Measured - Actual) / Actual ]* 100

Percent error = [ (143.6 - 173.1) / 173.1 ] * 100

The absolute value of (Measured - Actual) is taken,

Percent Error = [29.5 / 173.1 ] * 100

Percent Error = 0.1704 * 100 = 17.04%

4 0
3 years ago
Use the IUPAC nomenclature rules to give the name for this compound - Al2S3.
jonny [76]
Aluminium Sulfide
According to rules the positive specie is named first and the negative specie is named last.
6 0
3 years ago
Read 2 more answers
The "air bags" that are currently installed in automobiles to prevent injuries in the event of a crash are equipped with sodium
stellarik [79]

Answer:

0.0177 L of nitrogen will be produced

Explanation:

The decomposition reaction of sodium azide will be:

2NaN_{3}(s)--->2Na(s)+3N_{2}(g)

As per the balanced equation two moles of sodium azide will give three moles of nitrogen gas

The molecular weight of sodium azide = 65 g/mol

The mass of sodium azide used = 100 g

The moles of sodium azide used = \frac{mass}{molarmass}=\frac{100}{65}=1.54mol

so 1.54 moles of sodium azide will give = \frac{3X1.54}{2}=2.31mol

the volume will be calculated using ideal gas equation

PV=nRT

Where

P = Pressure = 1.00 atm

V = ?

n = moles = 2.31 mol

R = 0.0821 L atm / mol K

T = 25 °C = 298.15 K

Volume = \frac{P}{nRT}=\frac{1}{2.31X0.0821X298.15}=0.0177L

3 0
3 years ago
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