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ch4aika [34]
2 years ago
6

How many hydrophobic tails does a triacyl glycerol molecule have?

Chemistry
1 answer:
liberstina [14]2 years ago
8 0
Three identical fatty acid tails, or three different fatty acid tails (with different lengths or patterns of double bonds).
You might be interested in
In the ground-state electron configuration of fe3+, how many unpaired electrons are present? express your answer numerically as
Virty [35]
Answer:
            Iron has 5 unpaired electrons in Fe⁺³ state.

Explanation:

Iron having atomic number 26 has following electronic configuration in neutral state.

                             Fe =  1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d⁶

When Iron looses three electrons it attains +3 charge with following electronic configuration.

                             Fe⁺³ =  1s², 2s², 2p⁶, 3s², 3p⁶, 3d⁵

The five electrons in d-orbital exist in unpaired form as,

                          3(dz)¹, 3d(xz)¹, 3d(yz)¹, 3d(xy)¹, 3(dx²-y²)¹


3 0
3 years ago
A gas at STP occupies 22.4 L if the temperature is changed to 260 K and the pressures changed it to 0.50 ATM what will the new v
asambeis [7]

Answer:

The new volume will be 42, 7 L.

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. The conditions STP are: 1 atm of pressure and 273 K of temperature.

P1xV1/T1 =P2xV2/T2

1 atmx 22,4 L/273K = 0,5atmx V2/260K

V2=((1 atmx 22,4 L/273K )x 260K)/0,5 atm= 42, 67L

3 0
3 years ago
how much heat, in terms in q, would it take to produce the change in temperature indicated in the picture? what is your reasonin
STALIN [3.7K]

Answer:

1. q.

2. 2q.

3. 3q.

4. 6q.

Explanation:

We'll begin by calculating the specific heat capacity of the liquid. This can be obtained as follow:

Mass (m) = 25 g

Change in temperature (ΔT) = 20 °C

Heat (Q) = q

Specific heat capacity (C) =?

Q = MCΔT

q = 25 × C × 20

q = 500C

Divide both side by 500

C = q/500

C = 2×10¯³ qg°C

Therefore, the specific heat capacity of liquid is 2×10¯³ qg°C

Now, we shall determine the heat required to produce the various change in temperature as follow:

2. Mass (m) = 50 g

Change in temperature (ΔT) = 20 °C

Specific heat capacity (C) = 2×10¯³ qg°C

Heat (Q) =?

Q = MCΔT

Q = 50 × 2×10¯³ × 20

Q = 2q.

Therefore, the heat required is 2q.

3. Mass (m) = 25 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) = 2×10¯³ qg°C

Heat (Q) =?

Q = MCΔT

Q = 25 × 2×10¯³ × 60

Q = 3q.

Therefore, the heat required is 3q.

4. Mass (m) = 50 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) = 2×10¯³ qg°C

Heat (Q) =?

Q = MCΔT

Q = 50 × 2×10¯³ × 60

Q = 6q.

Therefore, the heat required is 6q.

4 0
3 years ago
Does entropy increase or decrease in the following processes?
DaniilM [7]
Where are the following answers?
8 0
3 years ago
Respuesta funcion oxido de Mg+2 + O-2
Effectus [21]

Answer:

Mg2 + O2 → 2MgO

Explanation:

Hope this helps!! I got it right.

7 0
2 years ago
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