All categories

3 years ago

Find the volume of an object that has a density of 3.14 g/mL and a mass of 52.9 g.

Chemistry

1 answer:

Natasha_Volkova [10]3 years ago

5 0

Answer:

The answer is

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass of object = 52.9 g

density = 3.14 g/mL

The volume of the object is

$volume = \frac{52.9}{3.14} \\ = 16.847133757...$

We have the final answer as

Hope this helps you

You might be interested in

What is the molar mass of Al2(SO3)3

Sonja [21]

The molar mass is 294.1527 g/mol

7 0

3 years ago

Which is stronger - the attractive forces between water molecules and chromium and chloride ions, or the combined ionic bond str

Allisa [31]

Out of the two, the forces between water molecules and chromium and chloride ions is greater. This is proven by the fact that chromium chloride is slightly soluble in water, about 565 grams per liter.
In order for a substance to be soluble, the attraction of the ions to the water molecules must exceed the attraction between its own molecules and the water molecules.

3 0

2 years ago

How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with

konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = $a=31 cm^2$

Thickness of the gold plating = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

$V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3$

Density of the gold = $d=19.3 g/cm^3$

$m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g$

Moles of gold = $\frac{29.915 g}{197 g/mol}=0.152 mol$

$Au^{3+}+3e^-\rightarrow Au$

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

$\frac{3}{1}\times 0.152 mol=0.456 mol$ of electrons

Number of electrons = N = $0.456\times \times 6.022\times 10^{23}$

Charge on single electron = $q=1.6\times 10^{-19} C$

Total charge required = Q

$Q=N\times q$

Amount of current passes = I = 8 Ampere

Duration of time = T

$I=\frac{Q}{T}$

$T=\frac{N\times q}{I}$

$=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s$

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

7 0

2 years ago

The nuclides I-131 and I-133 are classifieds as

sasho [114]

Isotopes are two atoms with the same number of protons, but a different number of neutrons. Because they have the same number of proton they are atoms of the same element, but with different masses.
so, the answer is c.
i hope this will help you

3 0

3 years ago

Read 2 more answers

Dalton's law of partial pressures states that the total pressure exerted by a mixture of gases is the sum of the pressures exert

Damm [24]

Answer: The given statement is true.

Explanation:

According to the Dalton's law, total pressure of a mixture of gases that do not react with each other is equal to the partial pressure exerted by each gas.

The relationship is as follows.

$p_{total} = \sum_{i=1}^{n} p_{i}$

or, $p_{total} = p_{1} + p_{2} + p_{3} + p_{4} + ......... + p_{n}$

where, $p_{1}, p_{2}, p_{3}$ ....... = partial pressure of individual gases present in the mixture

Also, relation between partial pressure and mole fraction is as follows.

$p_{i} = p_{total} \times x_{i}$

where, $x_{i}$ = mole fraction

Thus, we can conclude that the statement Dalton's law of partial pressures states that the total pressure exerted by a mixture of gases is the sum of the pressures exerted independently by each gas in the mixture, is true.

5 0

3 years ago