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mote1985 [20]
2 years ago
15

PLZZZZZZZ HELPPPP MEEEE ASAP CHEMISTRY QUESTION DOWN BELOW How can you identify a reversible reaction from a chemical equation?

Chemistry
2 answers:
zalisa [80]2 years ago
7 0

it's the third one The chemical equation will have two arrows pointing in different directions. !

enot [183]2 years ago
4 0

Answer:

the answer is option 1 2H2+O2

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natita [175]

Answer: Fundamental, Key, vital, crucial

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How efficient are electric engines
raketka [301]

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Electric engines have efficiencies of roughly 90% whilst combustion engines about 10% to 30%. This is because combustion engines emit much more heat, which is always energy that is not used as work, and thus increases inefficiency.

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3 years ago
Density of a piece of wood that has a measurement of 24 cm3 and 768 g
Brut [27]

Answer:

<h3>The answer is 32 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 768 g

volume = 24 cm³

We have

density =  \frac{768}{24}  \\

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<h3>32 g/cm³</h3>

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3 years ago
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The table below shows the content in mg of some chemical elements found in 100g of milk:
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5 0
3 years ago
A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.62 g of water at 52.3 oC in an insulated container. clear = 0.128
alisha [4.7K]

Answer: The final temperature of both the weight and the water at thermal equilibrium is 50.26^{o}C.

Explanation:

The given data is as follows.

mass = 7.62 g,           T_{2} = 10.8^{o}C

Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.

       q = mC \times \Delta T    

          = 7.62 g \times 4.184 J/^{o}C \times (52.3 - T)

Now, heat gained by lead will be calculated as follows.

       q = mC \times \text{Temperature change of lead}  

           = 2.04 \times 0.128 \times (T - 11.0)

According to the given situation,

     Heat lost = Heat gained

7.62 g \times 4.184 J/^{o}C \times (52.3 - T) = 2.04 \times 0.128 \times (T - 11.0)

        T = 50.26^{o}C

Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is 50.26^{o}C.

7 0
3 years ago
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