Question:
Sulfuric acid was once produced through the reaction of sulfur trioxide with water. Sulfur trioxide can form through the reaction of sulfur dioxide and oxygen gas. When nitrogen monoxide gas is added to the system, the reaction speeds up significantly because it proceeds through the following steps:
equations
Identify the catalyst in this reaction, explain how you know it is the catalyst, and describe how it increases the rate of the reaction.
Answer:
NO
It is present but not consumed
NO Lowers the activation energy of the reaction
Explanation:
A catalyst is a substance that is present in a chemical reaction and enables the reaction to occur at a faster rte but does not take part n the reaction
Therefore, whereby NO is not consumed, it is the catalyst
It functions by lowering the activation energy
Answer:
26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃
Explanation:
To determine the number of moles of O₂ that are needed to react completely with 35.0 mol of FeCl₃, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), and rule of three as follows: if 4 moles of FeCl₃ react with 3 moles of O₂, 35 moles of FeCl₃ with how many moles of O₂ will it react?
![molesofO_{2} =\frac{35 moles of FeCl_{3}*3 moles of O_{2} }{4 moles of FeCl_{3}}](https://tex.z-dn.net/?f=molesofO_%7B2%7D%20%3D%5Cfrac%7B35%20moles%20of%20FeCl_%7B3%7D%2A3%20moles%20of%20O_%7B2%7D%20%20%7D%7B4%20moles%20of%20FeCl_%7B3%7D%7D)
moles of O₂= 26.25 ≅ 26.3
<u><em>26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃</em></u>
![\huge \underbrace \mathfrak \red{Answer}](https://tex.z-dn.net/?f=%5Chuge%20%5Cunderbrace%20%5Cmathfrak%20%5Cred%7BAnswer%7D)
28%
Explanation:
mass of solute(KBr) = 3.73g
mass of solvent(H2O) = 131g
mass of solution = mass of solute + mass of solvent
= 3.73 + 131
= 134.73g
![\sf \large {mass \: percentage = \frac{mass \: of \: solute}{mass \: of \: solvent} \times 100} \\ \\ \sf mass \: percentage = \frac{3.73}{134.73} \times 100 \\ \\ \sf mass \: percentage = 0.028 \times 100 \\ \\ \sf mass \: percentage = 28\%](https://tex.z-dn.net/?f=%20%5Csf%20%5Clarge%20%7Bmass%20%5C%3A%20percentage%20%3D%20%20%5Cfrac%7Bmass%20%5C%3A%20of%20%5C%3A%20solute%7D%7Bmass%20%5C%3A%20of%20%5C%3A%20solvent%7D%20%20%5Ctimes%20100%7D%20%5C%5C%20%20%5C%5C%20%20%5Csf%20%20mass%20%5C%3A%20percentage%20%3D%20%20%5Cfrac%7B3.73%7D%7B134.73%7D%20%20%5Ctimes%20100%20%5C%5C%20%20%5C%5C%20%20%5Csf%20mass%20%5C%3A%20percentage%20%3D%20%200.028%20%5Ctimes%20100%20%5C%5C%20%20%5C%5C%20%20%5Csf%20mass%20%5C%3A%20percentage%20%3D%2028%5C%25)
Picoliter is a unit of measurement for liquids.
One picoliter = 1×10⁻⁹ mililiters
So:
19 mL ---- x pL
1×10⁻⁹ mL ---- 1 pL
1×10⁻⁹x = 19
x = 1,9 × 10¹⁰ pL
or 19,000,000,000 pL
Answer: 1.9 × 10¹⁰ pL