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Dmitrij [34]
3 years ago
15

Which of the following is an example of a chemical change? alcohol evaporating (b) water boiling

Chemistry
2 answers:
Elodia [21]3 years ago
5 0

Answer: Option (c) is the correct answer.

Explanation:

A property that does not bring any change in chemical composition of a substance are known as physical properties.

For example, shape, size, mass, volume, density, etc of a substance are all physical properties.

Water boiling, iodine vaporizing , and ice melting are all physical changes.

And, a property that changes chemical composition of a substance is known as chemical property.

For example, precipitation, reactivity, toxicity etc are chemical property.

Therefore, skin burning in the Sun is a chemical property.

Thus, we can conclude that skin burning in the Sun is an example of a chemical change.

stich3 [128]3 years ago
3 0
Alcohol evaporating, water boiling, iodine evaporating and ice melting are all examples of physical changes of state.

skin burning in the sun is a chemical change as the actual skin is chemically altered by the sun

hope that helps 
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A sample of quartz is put into a calorimeter (see sketch at right) that contains of water. The quartz sample starts off at and t
pashok25 [27]

Answer:

0.71 J/g°C

Explanation:

Here is the complete question

thermometer A 51.9 g sample of quartz is put into a calorimeter (see sketch at right) that contains 300.0 g of water. The quartz sample starts off at 97.8 °C and the temperature of the water starts off at 17.0 °C. When the temperature of the water stops changing it's 19.3 °C. The pressure remains constant at 1 atm. insulated container water sample Calculate the specific heat capacity of quartz according to this experiment. Be sure your answer is rounded to 2 significant digits. a calorimeter g °C

Solution

Since the temperature of the water increases from 17.0 °C to 19.3 °C, it means that it loses heat. Also, the final temperature of the quartz equals the final temperature of the water 19.3 °C. Since the quartz temperature decreases from 97.8 °C to 19.3 °C it loses heat.

So, heat lost by quartz, Q = heat gained by water, Q'

-Q = Q'

-mc(θ₂ - θ₁) = m'c'(θ₂ - θ₃) where m = mass of quartz = 51.9 g, c = specific heat capacity of quartz, θ₁ = initial temperature of quartz = 97.8 °C, θ₂ = final temperature of quartz = 19.3 °C, m' = mass of water = 300 g, c = specific heat capacity of water = 4.2 J/g °C , θ₃ = initial temperature of water = 17.0 °C, θ₂ = final temperature of water = 19.3 °C

Making c subject of the formula, we have

c = -m'c'(θ₂ - θ₃)/m(θ₂ - θ₁)

Substituting the values of the variables into the equation, we have

c = -300 g × 4.2 J/g °C(19.3 °C - 17.0 °C)/51.9 g(19.3 °C - 97.8 °C)

c = -1260 J/°C(2.3 °C)/51.9 g(-78.5 °C)

c = -2898 J/-4074.15 g°C

c = 0.711 J/g°C

c ≅ 0.71 J/g°C to 2 significant digits

5 0
3 years ago
Which group is likely to react with chlorine to form compounds in the form xcl?
Umnica [9.8K]
Group 1 elements since they have one outermost electron which they can give to chlorine which has 7 outermost electrons in order to form a stable compound.

Example 
Pottasium (K) + Chlorine (Cl) = Potassium Chloride (KCL)
4 0
3 years ago
What is a solvent ?
pantera1 [17]

Answer:

A solvent is a substance that dissolves a solute, resulting in a solution. A solvent is usually a liquid but can also be a solid, a gas, or a supercritical fluid.

Explanation:

3 0
3 years ago
How does a sample of water at 38 °C compare to a sample of water at 295 K?
Sidana [21]

Converting the temperature, 295 K from Kelvin to Celsius scale:

295 K - 273 = 22^{0} C

Water has a boiling point of 100^{0}C and a melting point of 0^{0} C

When we compare water at two different temperatures, 22^{0}C and 38^{0}C we can say that water is in liquid form at both these temperatures as both of them are quite below the boiling temperature and above the melting temperature.

The temperature difference between water at the given two temperatures = 38^{0}C - 22^{0}C = 16^{0}C

Water at 38^{0}C is at a higher temperature and so is warmer than water at a lower temperature of 22^{0}C (or 295 K).


7 0
3 years ago
Given the following data in the Determination of Molar Mass of CO2 lab : Mass (before rxn): test tube HCl(aq) stir bar capsule 2
RSB [31]

Answer:

.259 g

Explanation:

PV = nRT

n = PV / RT

= .986 x 0.144 / .082 x 293.6

= .005897 moles

= .005897 x 44 g

= .259 g

3 0
3 years ago
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