The products obtained from the dissociation of HNO₃ in water are hydronium ion, H₃O⁺ and nitrate ion, NO₃¯
An acid is a substance which when dissolved in water produces hydronium ion, H₃O⁺ as the only positive ion.
Strong acid ionize completely in water while weak acid only ionize to a certain degree (i.e partially) in water
Trioxonitrate (v) acid, HNO₃ is a strong acid and will ionize complete in water to form hydronium ion, H₃O⁺ and nitrate ion, NO₃¯ as illustrated below:
HNO₃ + H₂O —> H₃O⁺ + NO₃¯
Thus, the products for the dissociation equation are: hydronium ion, H₃O⁺ and nitrate ion, NO₃¯
Learn more: brainly.com/question/13173940
Answer:
a. add a little distilled water to see which layer the water adds to
Explanation:
The problem tells us to keep in mind two major aspects of the test: It has to be <em>simple</em>, as well as <em>non-destructive</em>:
- Adding distilled water can be made in under a minute, without requiring specialized laboratory equipment, unlike IR.
- It is also non-destructive, because the contents on either layer won't change due to the added distilled water.
To calculate percent composition, you first need to find the molar mass of C (carbon), H (hydrogen) and O (oxygen).
C is 12.01
H is 1.00
O is 16
Then multiply each by the number of atoms of each element in the formula (the number that comes after each element in the equation for example C6 means 6 carbon atoms.
C: 12.01 x 6= 72.06
H: 1x12= 12
O: 16x6= 96
Then add them up.
72.06+ 12+ 96= 180.06
Now find the percent composition of carbon.
72.06/ 180.06 x 100= 40.01%
So the answer is C 40%.
One mole of Na2SO4 is 6.022 * 10^(23) molecules. We can divide this into the quantity in the question to find a value of 1.5/6.022 = 0.2491 moles. Rounded to two significant figures and put in scientific notation, we can rewrite this quantity as 2.5 * 10^(-1) moles
Answer:
option A
an increase in entropy and a decrease in enthalpy
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