- Write equations for (a) the decomposition of carbon monoxide-

As a chemist for an agricultural products company, you have just developed a new herbicide,"Herbigon," that you think has the po

Ganezh [65]

Answer:

pH = 2.03

Explanation:

The pH can be calculated using the following equation:

$pH = -log [H_{3}O^{+}]$ (1)

The concentration of H₃O⁺ is calculated using the dissociation constant of the next reaction:

CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺

1.00 M

$K_{a} = \frac{[CH_{3}COO^{-}][H_{3}O^{+}]}{[CH_{3}COOH]}$

Solving the above equation for H₃O⁺, we have:

$[H_{3}O^{+}] = \frac{Ka*[CH_{3}COOH]}{[CH_{3}COO^{-}]}$ (2)

The dissociation constant is equal to:

$pKa = -log(Ka) \rightarrow Ka = 10^{-pKa} = 10^{-4.76} = 1.74 \cdot 10^{-5}$

Now, by solving the equation of the solubility product for Herbigon, we can find [CH₃COO⁻]:

CH₃COOX ⇄ CH₃COO⁻ + X⁺

5.00x10⁻³ M

$K_{sp} = [CH_{3}COO^{-}][X^{+}]$

$[CH_{3}COO^{-}] = \frac{K_{sp}}{[X^{+}]} = \frac{9.40 \cdot 10^{-6}}{5.00 \cdot 10^{-3}} = 1.88 \cdot 10^{-3} M$

By entering the values of [CH₃COO⁻] and Ka, into equation (2) we can calculate [H₃O⁺]:

$[H_{3}O^{+}] = \frac{1.74 \cdot 10^{-5}*[1.00]}{[1.88 \cdot 10^{-3}]} = 9.26 \cdot 10^{-3} M$

Hence, the pH is:

$pH = -log [H_{3}O^{+}] = -log [9.26 \cdot 10^{-3}] = 2.03$

Therefore, the pH must be 2.03 to yield a solution in which the concentration of X⁺ is 5.00x10⁻³M.

I hope it helps you!

6 0

4 years ago

Please help please help

Nastasia [14]

Explanation:

in this question, we're asked how to determine whether we have a metallic or nonmetallic substance.So what you want to do is one to remember that metals are malleable and Nonmetal are brittle. So if we were to hammer the metal, it would be very malleable, but the nonmetal would fall apart. And never we could just hammer the sample and see whether it was malleable. And therefore it would be a medal or a brittle and therefore being nonmetal.

7 0

2 years ago

Select the correct answer from each drop-down menu. In a voltaic cell, the electrons and is oxidized, while the electrons and is

KengaRu [80]

Given what we know, we can confirm that in a voltaic cell, the anode loses electrons and is oxidized, meanwhile, the cathode is reduced by gaining electrons.

<h3 /><h3>What is a voltaic cell?</h3>

It is described as an electrochemical cell.
These cells use chemical reactions to produce electrical energy.
During this reaction, an anode loses electrons, thus oxidizing.
Meanwhile, the cathode gains electrons and is reduced.

Therefore, given the nature of the voltaic cell, we can confirm that during its reaction, the anode is oxidized by losing electrons while the cathode becomes reduced by gaining them.

To learn more about electrical energy visit:

brainly.com/question/863273?referrer=searchResults

3 0

2 years ago

Convert 24 cm to the unit km

podryga [215]

K H D b d c m
So 10000 cm in a Km
A

6 0

4 years ago

Read 2 more answers

How many valence electrons are in each atom?

Zarrin [17]