Using the binomial distribution, it is found that the variance of the number that pass inspection in one day is 5.7.
For each component, there are only two possible outcomes, either it passes inspection, or it does not. The probability of a component passing inspections is independent of any other component, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
Probability of <u>exactly x successes on n repeated trials, with p probability</u>, and has variance given by:
![V(X) = np(1 - p)](https://tex.z-dn.net/?f=V%28X%29%20%3D%20np%281%20-%20p%29)
In this problem:
- 95% pass final inspection, hence
![p = 0.95](https://tex.z-dn.net/?f=p%20%3D%200.95)
- 120 components are inspected in one day, hence
.
The variance is given by:
![V(X) = np(1 - p) = 120(0.95)(0.05) = 5.7](https://tex.z-dn.net/?f=V%28X%29%20%3D%20np%281%20-%20p%29%20%3D%20120%280.95%29%280.05%29%20%3D%205.7)
The variance of the number that pass inspection in one day is 5.7.
To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377
Answer:
1
Step-by-step explanation:
hope this helps
Answer:
dummy
Step-by-step explanation:
you are stupid
Answer:
1) c 2)c 3)b
Step-by-step explanation:
Answer: The required factored form of the given expression is
![(x^4y^6+1)(x^8y^{12}-x^4y^6+1).](https://tex.z-dn.net/?f=%28x%5E4y%5E6%2B1%29%28x%5E8y%5E%7B12%7D-x%5E4y%5E6%2B1%29.)
Step-by-step explanation: We are given to find the factored form of the following algebraic expression:
![E=x^{12}y^{18}+1.](https://tex.z-dn.net/?f=E%3Dx%5E%7B12%7Dy%5E%7B18%7D%2B1.)
We will be using the following formula:
![a^3+b^3=(a+b)(a^2+ab+b^2).](https://tex.z-dn.net/?f=a%5E3%2Bb%5E3%3D%28a%2Bb%29%28a%5E2%2Bab%2Bb%5E2%29.)
Now, we have
![E\\\\=x^{12}y^{18}+1\\\\=(x^4y^6)^3+1^3\\\\=(x^4y^6+1)\{(x^4y^6)^2-x^4y^6\times1+1^2\}\\\\=(x^4y^6+1)(x^8y^{12}-x^4y^6+1).](https://tex.z-dn.net/?f=E%5C%5C%5C%5C%3Dx%5E%7B12%7Dy%5E%7B18%7D%2B1%5C%5C%5C%5C%3D%28x%5E4y%5E6%29%5E3%2B1%5E3%5C%5C%5C%5C%3D%28x%5E4y%5E6%2B1%29%5C%7B%28x%5E4y%5E6%29%5E2-x%5E4y%5E6%5Ctimes1%2B1%5E2%5C%7D%5C%5C%5C%5C%3D%28x%5E4y%5E6%2B1%29%28x%5E8y%5E%7B12%7D-x%5E4y%5E6%2B1%29.)
Thus, the required factored form of the given expression is
![(x^4y^6+1)(x^8y^{12}-x^4y^6+1).](https://tex.z-dn.net/?f=%28x%5E4y%5E6%2B1%29%28x%5E8y%5E%7B12%7D-x%5E4y%5E6%2B1%29.)