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tatyana61 [14]
3 years ago
9

Please help, need help asap!

Mathematics
1 answer:
cluponka [151]3 years ago
5 0
The correct answer is letter C
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Two sides of a triangle have lengths 18cm and 40cm describe the possible lengths of the third side
Paraphin [41]

Answer:

Step-by-step explanation:

a taingle adds up to 180 degrees if that helps

5 0
3 years ago
Suppose that each semester at a particular community college Manuel has to pay $1478 in tuition and $121 in fees.
Kamila [148]

Answer:

Step-by-step explanation:

<em>Let x be time, in semesters, remaining before Manuel graduates</em>.  We find that Manuel's expenses are:

$1478/semester in tuition, and

$121/semester in fees

1.  <u>x semesters remaining:  fees</u>

  Remaining cost for fees, y, is the product of the fee times the number of semesters, x:

y =($121/semester)*x

y = ($121)*x

2.  <u>x semesters remaining:  tuition</u>

  Remaining cost, y, is the product of the tuition (times the number of semesters, x.  

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

3.  <u>x semesters remaining:  tuition and fees</u>

  Remaining cost, y, is the sum of the products of the tuition (times the number of semesters, and the fees (tix.  

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

5 0
1 year ago
Find the volume of cylinder shaped cup. Use 3.14 for pi. Round your answer
IRINA_888 [86]
Volume = pi * radius^2 * height

= 3.14 * 5^2 * 13

= 3.14 * 25 * 13

= 1020.5
5 0
3 years ago
What % of $100 = $90
Harlamova29_29 [7]

Answer: 90%

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What are the zeros of the function f(x)=x^2-2x-15?
valkas [14]
To find the zeros of this function, we must first set the entire function equal to 0

f(x) = x² - 2x - 15 = 0

Since this is a quadratic function, we must use the quadratic formula, which is:

\frac{-b +/-  \sqrt{b^{2} - 4(a)(c) } }{2a}

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15

Now let's plug those in:

\frac{-(-2) +/- \sqrt{(-2)^{2} - 4(1)(-15) } }{2(1)}

which simplifies to:

\frac{2 +/- \sqrt{(4 + 60} }{2}

Simplified further:

\frac{2 +/- \sqrt{(64} }{2}
\frac{2 +/- 8 }{2}
And divide it by the 2 on the bottom gives us:

2 +/- 4

2+4 = 6
2-4 = -2

So the zeros of this function are -2 and 6
6 0
3 years ago
Read 2 more answers
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