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rusak2 [61]
4 years ago
9

Suzie stands on a pedestal and touches the dome of a running Van de Graaf generator. In a few seconds she observes her hair stan

ding on end. Explain this observation.
A)
Each hair was induced with a positive charge. Each hair repels against its neighbor and stands up.


B)
Each hair was induced with a positive charge. Each hair is attracted to its neighbor and stands up.


C)
Half of Suzie's hairs were charged negative, and the other half charged positive. The different charged hairs repel each other and stand up.


D)
Half of Suzie's hairs were charged negative, and the other half charged positive. The different charged hairs attract to each other and stand up.
Physics
2 answers:
arlik [135]4 years ago
4 0

Answer:A

Explanation:

Fofino [41]4 years ago
3 0

Answer:

A)  

Each hair was induced with a positive charge. Each hair repels against its neighbor and stands up.

Explanation:

When we touch the Van-de-Graff generator then due to high potential of the generator the charge is induced in our hairs.

Due to induction of charge in hairs all the hairs get similar charge and this similar charge is on each hair is along its whole length.

Now due to coulombs law all hairs are repelling each other due to similar nature of charge and this repulsion against each neighboring hair will stand the hairs upwards

so correct answer will be

A)  

Each hair was induced with a positive charge. Each hair repels against its neighbor and stands up.

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zmey [24]

Answer:

54.3N

Explanation:

The normal force is perpendicular to the slope, so:

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F(friction)=mu*F(normal)

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F/x = constant

F₁/x₁ = F₂/x₂
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The swim bladder of a fish helps keep the fish from sinking by_______.
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The bellow of a territorial bull hippopotamus is measured at 100 dB above the threshold of hearing. What is the sound intensity?
Dmitriy789 [7]

Answer:

Explanation:

The hippopotamus hearing threshold is 100dB

β = 100 dB

The threshold of human hearing is Io = 1 × 10^-12 W/m²

The sound intensity level is given as

β = 10•Log(I / Io)

100 = 10•Log(I / Io)

Divided Both sides by 10

100 / 10 = Log(I / Io)

10 = Log(I / Io)

Take inverse Logarithm ( antilog) of both sides

10^10 = 10^[Log(I / Io)]

10^10 = I / Io

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