Answer:
0.67 s
Explanation:
This is a simple harmonic motion (SHM).
The displacement, 
, of an SHM is given by
A is the amplitude and 
is the angular frequency.
We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or 
radian.
From trigonometry, 
if A and B are complementary.
At 
, 
So
At 
, 
The period, 
, is related to by
Answer:
0.0360531138247 V/m
Explanation:
= Resistivity of gold = 
(General value)
I = Current = 940 mA
d = Diameter = 0.9 mm
A = Area = 
E = Electric field
Resistivity is given by
The electric field in the wire is 0.0360531138247 V/m
pythagoras' theorem on right angled triangle. sides 125, 65
sqrt (125^2 +65^2)
Answer:
a. 2.53 μJ b. It will move away
Explanation:
a. What is the electric potential energy between the particles?
The electric potential energy U = kq₁q₂/r where k = 9 × 10⁹ Nm²/C², q₁ = 4.1 nC = 4.1 × 10⁻⁹ C, q₂ = 2.4 nC = 2.4 × 10⁻⁹ C and r = distance between charges = 3.5 cm = 3.5 × 10⁻² m.
Substituting the values of the variables into U, we have
U = kq₁q₂/r²
U = 9 × 10⁹ Nm²/C² × 4.1 × 10⁻⁹ C × 2.4 × 10⁻⁹ C/3.5 × 10⁻² m
U = 88.56 × 10⁻⁹ Nm²/3.5 × 10⁻² m
U = 25.3 × 10⁻⁷ Nm
U = 2.53 × 10⁻⁶ Nm
U = 2.53 × 10⁻⁶ J
U = 2.53 μJ
b. And if the second particle is released will it move forward or away from the source charge.
It will move away from the source charge since they have the same sign of charge. Since, opposite charges repel.
THE ANSWER IS IN ATTACHED PICTURE....
