Answer:
Explanation:
C) What is the multiplicity of Proton-alpha's signal in this scenario when there are 2 identical protons "next door"?
Based on n+1 rule. Here n=2 (identical beta protons).
2+1=3
So the multiplicity of alpha proton is triplet, .
D) For molecules containing only single bonds (we'll discuss the influence of double bonds in a future lecture), what is the adjective that describes the position of protons that split a "next door neighbor's" signal?
The meaning of the adjective is this: the multiplicity of beta protons is singlet only (no spliting) in absence of alpha proton . But beta protons splits as doublet (n=1) in the presence of alpha proton,
E) How many bonds connect these "splitting next door neighbors"?
There are 3 bonds in between alpha and beta protons in a molecule.
F) What is the multiplicity of the Proton-betas' signal?
Following the n+1 rule, here n=1 (1 alpha proton) so 1+1=2. Hence it is a doublet.
The total kinetic energy of the gas sample is 3.3 KJ
<h3>What is kinetic energy? </h3>
This is the energy possessed by an object in motion. Mathematically, it can be expressed as:
KE = ½mv²
Where
- KE is the kinetic energy
- m is the mass
- v is the velocity
<h3>How to determine the mass of the fluorine gas</h3>
- Molar mass of fluorine gas = 38 g/mol
- Mole of fluorine gas = 1 mole
- Mass of fluorine gas = ?
Mass = mole × molar mass
Mass of fluorine gas = 1 × 38
Mass of fluorine gas = 38 g
<h3>How to determine the KE of the gas sample</h3>
- Mass (m) = 38 g = 38 / 1000 = 0.038 Kg
- Velocity (v) = 415 m/s
- Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 0.038 × 415²
KE = 3272.275 J
Divide by 1000 to express in kilojoule
KE = 3272.275 / 1000
KE = 3.3 KJ
Learn more about energy:
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Answer:
D
Explanation:
The SI unit for density is the kilogram per cubic meter (kg/m3 ).
Answer:
12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.
Explanation:
Radioactive isotopes decay exponentially in time, the mass of the isotope (
), in grams, is described by the formula in time (
), in minutes:
(1)
Where:
- Initial mass of the isotope, in grams.
- Time constant, in minutes.
In addition, the time constant associated with the isotope decay can be described in terms of half-life (
), in minutes:
(2)
If we know that 
, 
and 
, then the time taken by the isotope is:
12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.
