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3 years ago

15

Using the information in the table to the right, calculate the enthalpy of combustion of 1 mole of acetylene for the reaction

1 answer:

barxatty [35]3 years ago

8 0

The enthalpy of combustion of 1 mole of acetylene for the reaction using the information in the table (attached as figure) is - 1,256 kJ/mol

<h3>What is Enthalpy of combustion ?</h3>

The enthalpy of combustion of a substance is defined as the heat energy given out when one mole of a substance burns completely in oxygen.

Hence, The enthalpy of combustion of 1 mole of acetylene for the reaction using the information in the table is - 1,256 kJ/mol

Learn more about Enthalpy here ;

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The molar heat capacity of a compound with the formula C2H6SO is 88.0 J/mol-K. The specific heat of this substance is __________

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Answer : The specific heat of this substance is, 1.13 J/g.K

Explanation :

Molar heat capacity : It is defined as the amount of heat absorbed by one mole of a substance to raise its temperature by one degree Celsius.

As we are given that the chemical formula of compound is, $C_2H_6SO$

First we have to calculate the molar mass of given compound.

Molar mass of $C_2H_6SO$ = $2(12g/mol)+6(1g/mol)+32g/mol+16g/mol$

Molar mass of $C_2H_6SO$ = 78 g/mol

Now we have to calculate the specific heat of this substance.

Specific heat of this substance = $\frac{\text{Molar heat capacity of a compound}}{\text{Molar mass of }C_2H_6SO}$

Specific heat of this substance = $\frac{88.0J/mol.K}{78g/mol}$

Specific heat of this substance = 1.13 J/g.K

Thus, the specific heat of this substance is, 1.13 J/g.K

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