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Fantom [35]
3 years ago
12

For the reaction 2HNO3 + Mg(OH)2 → Mg(NO3) 2 + 2H2O, how many grams of magnesium nitrate are produced from 4 grams of nitric aci

d, HNO3 ?
Round your answer to the nearest tenth. Do not round your answers until the last step of the problem. If you do, the computer might mark your answer incorrect and you will be asked to complete your second trial for this assessment.

Use the following molar masses:

Element Molar Mass
Hydrogen 1
Magnesium 24
Nitrogen 14
Oxygen 16
Chemistry
1 answer:
kotegsom [21]3 years ago
8 0

Answer:

First check to make sure you have a balanced equation

Second use mole ratios to set up what you need to know

Finally convert the moles to grams using the correct molecular weight

I will get you started

According to the reaction above, one mole of Magnesium Nitrate is produced from 2 moles of Nitric Acid

1 mole of Mg(NO3)2/2 moles of HNO3

5 grams of Nitric acid contains

5 g * 1 mole/63 g of Nitric Acid = 0.079365079 moles

Explanation:

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The vapor pressure of water is 1.00 atm at 373 K, and the enthalpy of vaporization is 40.68 kJ mol!. Estimate the vapor pressure
Yuki888 [10]

Answer:

The vapor pressure at temperature 363 K is 0.6970 atm

The vapor pressure at 383 K is 1.410 atm

Explanation:

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature T_1

P_2 = vapor pressure at temperature T_2

\Delta H_{vap} = Enthalpy of vaporization  

R = Gas constant = 8.314 J/mol K

1) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =363 K

T_2 = final temperature =373 K

P_2=1 atm, P_1=?

Putting values in above equation, we get:

\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]

P_1=0.69671 atm \approx 0.6970 atm

The vapor pressure at temperature 363 K is 0.6970 atm

2) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =373 K

T_2 = final temperature =383 K

P_1=1 atm, P_2?

Putting values in above equation, we get:

\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]

P_2=1.4084 atm \approx 1.410 atm

The vapor pressure at 383 K is 1.410 atm

8 0
3 years ago
How many moles are there in 2.35 grams of H2O?
Marysya12 [62]

Answer:

the answer is 0.13 moles

7 0
4 years ago
In lab, a dialysis bag was filled with a 10% sucrose solution and placed in an unlabeled beaker filled with clear liquid. The di
DaniilM [7]

Answer:

Of lower concentration or less concentrated

Explanation:

Osmosis is the movement of solvent from a region of lower concentration of solute to a region of higher concentration of solute through a semipermeable membrane in order to equalize the concentration of the solutions on both sides.

Since the membrane of the bag is semipermeable, then the fact that the bag in the beaker decreased in size, lost volume, and became flaccid indicates that the solution in the bag is of lower solute concentration than the solution in the beaker hence the movement of water molecules into the beaker by osmosis.

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Vanyuwa [196]

Answer:

temperatures within the outer core range from 7,200 to 9,000 F. Pressure also increases in the outer core due in part to the weight of the crust and mantle above.The Earth's magnetic field is generated by the outer core.

Explanation:

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properties of elements within a ________ on the periodic table change in a predictable way from one side of the table to the oth
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