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gayaneshka [121]
3 years ago
14

How to titrate cocacola because of its dark colour

Chemistry
2 answers:
ivolga24 [154]3 years ago
7 0

<u>Answer and Explanation</u>

<em>__________________________________________________________</em>

<em>All of the Information below is not owned by me, it is owned by CCBCMD.</em>

<em>__________________________________________________________</em>

<em>Colas are also carbonated beverages. The carbonation can produce some carbonic acid in the  Cola, which would affect your results. Therefore, to ensure that you are only titrating the  phosphoric acid you will use de-carbonated soda. This can easily be obtained by gently  heating the soda, or as you may already know, by rapidly shaking the bottle. It is also important that we do not use diet Colas since the artificial sweeteners that they contain have  acidic functional groups that will also interfere with the titration.</em>

<em>__________________________________________________________</em>

<h2>1</h2>

<em>Use a 25.00-mL pipet to deliver exactly 25.00 mL of room temperature, de-carbonated </em>

<em>Cola into a 250-mL beaker. Check out a magnetic stir bar and gently add it to the </em>

<em>beaker. Place the beaker on a stir plate. Set up a pH meter so that the probe is   completely immersed, but in a way that the stir bar will not hit it. The tip of the probe </em>

<em>has a thin glass membrane. Handle it with care! Position the beaker so that the stir bar </em>

<em>is as close to the center of the beaker as possible for optimal stirring. It should stir </em>

<em>rapidly enough to ensure thorough mixing but not so rapidly as to cause splattering. </em>

<em>__________________________________________________________</em>

<h2>2</h2>

<em>Obtain about 75 mL of 0.0100 M NaOH in a beaker. Use this NaOH to fill a buret. </em>

<em>Remember that you should always rinse a buret 2-3 times with the solution that you are </em>

<em>about to put into it and remove air bubbles at the buret tip. If you do not remember how </em>

<em>The initial level of the NaOH should be at exactly </em>

<em>0.00 mL. Once the buret is ready, place it over the beaker containing the Cola</em>

<em>__________________________________________________________</em>

<em>Hope this helps! <3</em>

<em>__________________________________________________________</em>

Bas_tet [7]3 years ago
4 0

Answer:

add baking soda maybe

Explanation:

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Answer:

The volume of solution in liters required to make a 0.250 M solution from 3.52 moles of solute is 14.08 liters of solution

Explanation:

The question relates to the definition of the concentration of a solution which is the number of moles per liter (1 liter = 1 dm³) of solution

Therefore we have;

The concentration of the intended solution = 0.250 M

Therefore, the number of moles per liter of the required resolution = 0.250 moles

Therefore, the concentration of the required solution = 0.250 moles/liter

The volume in liters of the required solution that will have 3.52 moles of the solute is given as follows;

The required volume of solution = The number of moles of the solute/(The concentration of the solution)

∴ The required volume of solution = 3.52 moles/(0.250 moles/liter) = 14.08 liters

The required volume of solution to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.

Therefore the number of liters required to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.

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The molality is temp independent whereas molarity is temperature dependent. Justify.
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Molality is obtained by dividing the number of moles of solute by the mass in kilogram of the solvent. None of the dimensions is dependent in temperature. On the other hand, molarity is obtained by dividing the number of moles of solute by the volume in liters of the solution. Volume is temperature dependent. 
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Reversible reaction and examples on them
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Answer:

Here are three examples  

Explanation:

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Example 1

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Example 2

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Determine the equilibrium constant, Keq, at 25°C for the reaction
adelina 88 [10]

Explanation:

The given chemical reaction is:

2Br^- (aq) + I_2(s)  Br_2(l) + 2I^- (aq)

E^ocell=oxidation potential of anode + reduction potential of cathode\\

The relation between Eo cell and Keq is shown below:

deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell

The value of Eo cell is:

Br- undergoes oxidation and I2 undergoes reduction.

Reduction takes place at cathode.

Oxidation takes place at anode.

Hence,

E^ocell= (-1.07+0.53)V\\=-0.54V

F=96485 C/mol

n=2 mol

R=8.314 J.K-1.mol-1

T=298K

Substitute all these values in the above formula:

ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3

Answer:

Keq=6.13x10^33

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A marble has more density than an inflated balloon.
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