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3 years ago

How to titrate cocacola because of its dark colour

Chemistry

2 answers:

ivolga24 [154]3 years ago

7 0

Answer and Explanation

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All of the Information below is not owned by me, it is owned by CCBCMD.

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Colas are also carbonated beverages. The carbonation can produce some carbonic acid in the Cola, which would affect your results. Therefore, to ensure that you are only titrating the phosphoric acid you will use de-carbonated soda. This can easily be obtained by gently heating the soda, or as you may already know, by rapidly shaking the bottle. It is also important that we do not use diet Colas since the artificial sweeteners that they contain have acidic functional groups that will also interfere with the titration.

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Use a 25.00-mL pipet to deliver exactly 25.00 mL of room temperature, de-carbonated 

Cola into a 250-mL beaker. Check out a magnetic stir bar and gently add it to the 

beaker. Place the beaker on a stir plate. Set up a pH meter so that the probe is completely immersed, but in a way that the stir bar will not hit it. The tip of the probe 

has a thin glass membrane. Handle it with care! Position the beaker so that the stir bar 

is as close to the center of the beaker as possible for optimal stirring. It should stir 

rapidly enough to ensure thorough mixing but not so rapidly as to cause splattering. 

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Obtain about 75 mL of 0.0100 M NaOH in a beaker. Use this NaOH to fill a buret.

Remember that you should always rinse a buret 2-3 times with the solution that you are

about to put into it and remove air bubbles at the buret tip. If you do not remember how

The initial level of the NaOH should be at exactly

0.00 mL. Once the buret is ready, place it over the beaker containing the Cola

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Hope this helps! <3

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Bas_tet [7]3 years ago

4 0

Answer:

add baking soda maybe

Explanation:

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The activation energy for the reaction NO2(g)+CO(g)⟶NO(g)+CO2(g) is Ea = 75 kJ/mol and the change in enthalpy for the reaction i

lapo4ka [179]

Answer:

= 100kJ

Explanation:

The reverse reaction's activation energy of a reaction is the activation energy of the forward reaction plus ΔH of the reaction:

Ea of forward reaction =75kJ

∆H = -175 kJ/mol

Ea of reverse reaction = 75 +(-175)

= 100kJ

Note that a reverse reaction is one which can proceed in both direction depending on the conditions.

6 0

3 years ago

A piece of unknown metal weighs 348g. When the metal piece absorbs 6.64kj of heat , its temperature increases from 24.4C to 43.6

Morgarella [4.7K]

Answer:

This metal could be the aluminium with a specific heat of $H = 993 \frac{J}{kgC}$

Explanation:

A pie of unknown metal presents a mass (M) of 348 g. This metal is heated using energy (E) of 6.64 kJ and the temperature increases from T1 =24.4 to T2 =43.6°C. We can calculate the specific heat (H) of this metal as follows

$H = \frac{E}{M*(T2-T1)}$

We can replace previously presented data in this equation. After simplifying and converting to adequated units, we found that

$H = \frac{6640 J}{0.348 Kg*(43.6-24.4) C} =\frac{6640 J}{6.686 KgC}$

Finally, the specific heat of this metal is

$H = 993 \frac{J}{kgC}$

The aluminium could be the metal, its specific heat is similar to that found in this problem.

Finally, we can conclude that this metal could be the aluminium with a specific heat of $H = 993 \frac{J}{kgC}$

7 0

3 years ago

Answer questions using the two magnetic field models (will mark brainliest)

JulijaS [17]

Answer:

2. A

3.B

4.B

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3 years ago

Who can tell me the half reaction about cucumber battery

xeze [42]

I've prepared some analysis and cucumbers do have many comparable properties to potatoes, tomatoes, and lemons, all of which I know do work. So I would presume that cucumbers would also work. I would recommend trying it yourself to perceive. I'd love to hear the outcomes of your experiment. ;)

6 0

3 years ago

an unknown molecule is found to consist of 24.2% carbon by mass, 4.0% hydrogen by mass and the remaining mass is due to chlorine

Paha777 [63]

Answer:

C3 H6 Cl 3

Explanation:

C -24.2%

H - 4.0%

Cl - (100-24.2 - 4.0)=73.8 %

We can take 100g of the substance, then we have

C -24.2 g

H - 4.0 g

Cl - 73.8 g

Find the moles of these elements

C -24.2 g/12.0 g/mol =2.0 mol

H - 4.0 g/1.0 g/mol = 4. 0 mol

Cl - 73.8 g/ 35.5 g/mol = 2.1 mol

Ratio of these elements gives simplest formula of the substance

C : H : Cl = 2 : 4 : 2 = 1 : 2 : 1

CH2Cl

Molar mass (CH2Cl) = 1*12.0 +2*1.0 + 1*35.5 = 49.5 g/mol

Real molar mass = 150 g/mol

real molar mass/ Molar mass (CH2Cl) = 150 /49.5=3

So, Real formula should be C3 H6 Cl 3.

4 0

4 years ago

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